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hammer [34]
3 years ago
10

Which set of side lengths belong to a right triangle?

Mathematics
2 answers:
Troyanec [42]3 years ago
4 0

Answer:

10 cm,6 cm,8 cm

Step-by-step explanation:

alexdok [17]3 years ago
3 0

Answer:

10 cm, 6cm, 8cm

Step-by-step explanation:

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When baking a cake you can choose between a round pan with a 9 in. diameter and a 8 in. times 11 in. rectangular pan?
ivanzaharov [21]

Question says that there are two type of pans.

First pan has diameter of 9 inches.

Second pan has dimension 8 inches by 11 inches. Which means second pan is rectangular.

It seems you missed few parts of the question like what we have to do with it. I searched for similar question on internet and found that they are finding surface area of the both pans so i will tell you how to find that.


Radius of the circular pan = diameter/2 = 9/2 = 4.5 inches

Then surface area of the first (circular) pan = \pi r^2 = 3.14 *4.5^2 = 63.585 square inches.


Now surface area of second (rectangular) pan is given by formula of area of rectangle

Area = Length * width = 8*11= 88 square inches.

4 0
3 years ago
9 + 9h<br> =<br> 10h + 2 is this infinite solution
Kamila [148]

Answer:

no, h=7

Step-by-step explanation:

9+9h = 10h+2

9=h+2

7=h

7 0
2 years ago
21 quarters out of 186 quarters simplest form
posledela
21/186
Answer: 7/62
Hope this helps!!!!!!!

4 0
3 years ago
Read 2 more answers
We are throwing darts on a disk-shaped board of radius 5. We assume that the proposition of the dart is a uniformly chosen point
Vlad1618 [11]

Answer:

the probability that we hit the bullseye at least 100 times is 0.0113

Step-by-step explanation:

Given the data in the question;

Binomial distribution

We find the probability of hitting the dart on the disk

⇒ Area of small disk / Area of bigger disk

⇒ πR₁² / πR₂²

given that; disk-shaped board of radius R² = 5, disk-shaped bullseye with radius R₁ = 1

so we substitute

⇒ π(1)² / π(5)² = π/π25 = 1/25 = 0.04

Since we have to hit the disk 2000 times, we represent the number of times the smaller disk ( BULLSEYE ) will be hit by X.

so

X ~ Bin( 2000, 0.04 )

n = 2000

p = 0.04

np = 2000 × 0.04 = 80

Using central limit theorem;

X ~ N( np, np( 1 - p ) )

we substitute

X ~ N( 80, 80( 1 - 0.04 ) )

X ~ N( 80, 80( 0.96 ) )

X ~ N( 80, 76.8 )

So, the probability that we hit the bullseye at least 100 times, P( X ≥ 100 ) will be;

we covert to standard normal variable

⇒ P( X ≥  \frac{100-80}{\sqrt{76.8} } )

⇒ P( X ≥ 2.28217 )

From standard normal distribution table

P( X ≥ 2.28217 ) = 0.0113

Therefore, the probability that we hit the bullseye at least 100 times is 0.0113

3 0
3 years ago
Find all solutions for a triangle with A = 30°, a = 4, and b = 8.
Artemon [7]
The answer will be b
5 0
3 years ago
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