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ioda
3 years ago
10

A boat leaves the dock and travels 9 miles due south, then 12 miles due west.

Mathematics
1 answer:
loris [4]3 years ago
4 0
The answer would be A. 15mi
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Max z = 3x1 + 5x2 subject to: 7x1 + 12x2 ≤ 136 3x1 + 5x2 ≤ 36 x1, x2 ≥ 0 and integer find the optimal solution. what is the valu
Reptile [31]
The second constraint is the same as the objective function, so your problem boils down to finding integer solutions to
.. 3x1 +5x2 = 36

There are 3 solutions. They are (x1, x2) = (12, 0), (7, 3), (2, 6)

The value of the objective function there is (obviously) 36.
4 0
3 years ago
What is 4,002 expressed in scientific notation?
Simora [160]

Answer:

4.002 x 10^3

Step-by-step explanation:

4 0
2 years ago
I'm having trouble with #2. I've got it down to the part where it would be the integral of 5cos^3(pheta)/sin(pheta). I'm not sur
Butoxors [25]
\displaystyle\int\frac{\sqrt{25-x^2}}x\,\mathrm dx

Setting x=5\sin\theta, you have \mathrm dx=5\cos\theta\,\mathrm d\theta. Then the integral becomes

\displaystyle\int\frac{\sqrt{25-(5\sin\theta)^2}}{5\sin\theta}5\cos\theta\,\mathrm d\theta
\displaystyle\int\sqrt{25-25\sin^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta
\displaystyle5\int\sqrt{1-\sin^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta
\displaystyle5\int\sqrt{\cos^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta

Now, \sqrt{x^2}=|x| in general. But since we want our substitution x=5\sin\theta to be invertible, we are tacitly assuming that we're working over a restricted domain. In particular, this means \theta=\sin^{-1}\dfrac x5, which implies that \left|\dfrac x5\right|\le1, or equivalently that |\theta|\le\dfrac\pi2. Over this domain, \cos\theta\ge0, so \sqrt{\cos^2\theta}=|\cos\theta|=\cos\theta.

Long story short, this allows us to go from

\displaystyle5\int\sqrt{\cos^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta

to

\displaystyle5\int\cos\theta\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta
\displaystyle5\int\dfrac{\cos^2\theta}{\sin\theta}\,\mathrm d\theta

Computing the remaining integral isn't difficult. Expand the numerator with the Pythagorean identity to get

\dfrac{\cos^2\theta}{\sin\theta}=\dfrac{1-\sin^2\theta}{\sin\theta}=\csc\theta-\sin\theta

Then integrate term-by-term to get

\displaystyle5\left(\int\csc\theta\,\mathrm d\theta-\int\sin\theta\,\mathrm d\theta\right)
=-5\ln|\csc\theta+\cot\theta|+\cos\theta+C

Now undo the substitution to get the antiderivative back in terms of x.

=-5\ln\left|\csc\left(\sin^{-1}\dfrac x5\right)+\cot\left(\sin^{-1}\dfrac x5\right)\right|+\cos\left(\sin^{-1}\dfrac x5\right)+C

and using basic trigonometric properties (e.g. Pythagorean theorem) this reduces to

=-5\ln\left|\dfrac{5+\sqrt{25-x^2}}x\right|+\sqrt{25-x^2}+C
4 0
3 years ago
Read 2 more answers
t takes Phillip 7 hours to proof a chapter of Hawkes Learning Systems' Intermediate Algebra book and it takes Kim 3 hours. How l
Leya [2.2K]

Answer:

2.1 hrs

Step-by-step explanation:

In 1 hr, Phillip would have proofed 1/7 of the chapter. In 1 hr, Kim would have proofed 1/3 of the chapter. So, together in 1 hr, they would have proofed 10/21 of the chapter. So, it would take 21/10 or 2.1 hrs to proof the whole chapter together.

5 0
3 years ago
5 baseballs to 25 softballs in simplest form
sashaice [31]

Answer:

1/5

Step-by-step explanation:

5 baseballs to 25 softballs

=

1 baseballs to 5 softballs in simplest form

5 0
4 years ago
Read 2 more answers
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