Answer:
6 packs
Step-by-step explanation:
The answer is 6 packs of tickets. The reasoning behind this is that the graph literally states it. If you go to the side of the graph that shows how much money they spend, and look at 27 you can see that they bought 6 packs of tickets for 27 dollars. If you wanna know how to solve it like mathematically you really wouldn't need to but you can see that if you were to buy 2 packs of tickets it would be 9 dollars (according to the graph) which if we divide 9 by 2 you figure out that for one pack of tickets its $4.50. Then you could easily just divide 27 by 4.5 and you would be left with 6, the answer. Again though u really don't need to do that the graph shows it for you so these questions should be pretty easy. Hope this helped! (also sorry I'm not the best at explaining things but I tried, Goodluck!!) :)
Average rate of change over interval [a,b]: r=[f(b)-f(a)]/(b-a)
In this case the interval is [0,2], then a=0, b=2
r=[f(2)-f(0)]/(2-0)
r=[f(2)-f(0)]/2
1) First function: h(x)
r=[h(2)-h(0)]/2
x=2→h(2)=(2)^2+2(2)-6
h(2)=4+4-6
h(2)=2
x=0→h(0)=(0)^2+2(0)-6
h(0)=0+0-6
h(0)=-6
r=[h(2)-h(0)]/2
r=[2-(-6)]/2
r=(2+6)/2
r=(8)/2
r=4
2) Second function: f(x)
A function, f, has an
x-intercept at (2,0)→x=2, f(2)=0
and a y-intercept at (0,-10)→x=0, f(0)=-10
r=[f(2)-f(0)]/2
r=[0-(-10)]/2
r=(0+10)/2
r=(10)/2
r=5
3) Third function: g(x)
r=[g(2)-g(0)]/2
From the graph:
g(2)=6
g(0)=2
r=(6-2)/2
r=(4)/2
r=2
4) Fourth function: j(x)
r=[j(2)-j(0)]/2
From the table:
x=2→j(2)=-8
x=0→j(0)=4
r=(-8-4)/2
r=(-12)/2
r=-6
Answer:
Pairs
1) h(x) 4
2) f(x) 5
3) g(x) 2
4) j(x) -6
Easy
just find the slope between those 2 points
f(-6)=6
f(-3)=0
slope=rise/run=-6/3=-2
slope is -2
A is answer
Answer:
y=1/6 · ln |x|+c .
Step-by-step explanation:
From Exercise we have the differential equation
4xy dx= (4y6x²) dy.
We calculate the given differential equation, we get
4xy dx= (4y6x²) dy
xy dx=6yx² dy
6 dy=1/x dx
∫ 6 dy=∫ 1/x dx
6y=ln |x|+c
y=1/6 · ln |x|+c
Therefore, we get that the solution of the given differential equation is
y=1/6 · ln |x|+c .
6) C, B, A, D, E
7) C, A, E, B, D