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rosijanka [135]
3 years ago
13

Whoever helps with number 3 gets brainliest answer and 10 points :)

Mathematics
2 answers:
statuscvo [17]3 years ago
4 0
53 is the mean
70 is the range
there is no mode
51 is the median
MaRussiya [10]3 years ago
3 0
<span><span>Mean:53
</span><span>Median:51
</span><span>Range:70
</span><span>Mode:<span>All values appeared just once.</span></span></span>
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What would the diagram look like
Harlamova29_29 [7]
Hey man ill be honest idrk but it is kinda hard to see

8 0
3 years ago
If a gas tank can hold 30 gallons, how many gallons does it contain when it is three-fifths full?​
dalvyx [7]

Answer:

<em>3/5 of 30 = (3/5)*30</em>

<em>3/5 of 30 = (3/5)*303/5 of 30 = (3*30)/5</em>

<em>3/5 of 30 = (3/5)*303/5 of 30 = (3*30)/53/5 of 30 = 90/5</em>

<em>3/5 of 30 = (3/5)*303/5 of 30 = (3*30)/53/5 of 30 = 90/53/5 of 30 = 18</em>

<em>3/5 of 30 = (3/5)*303/5 of 30 = (3*30)/53/5 of 30 = 90/53/5 of 30 = 18So when the tank is 3/5 full, there are 18 gallons in the tank.</em>

6 0
2 years ago
Can you also show the work plz
ratelena [41]

Answer:

$29,900

Growth

22%

Step-by-step explanation:

Initial value is when t = 0

v(0) = 29900(1.22)^0

v(0) = 29900(1)

v(0) = 29900

-------------------------

Growth

because 1.22 is greater than 1

----------------------------

Yearly value change

1.22 - 1 = 0.22

0.22 * 100 = 22

22%

4 0
2 years ago
-7 7/8 + (3 5/6) please help me im going to fail​
cricket20 [7]
(Assuming that theses are mixed number fractions) the exact form is -97/24, decimal form -4.0416 repeated, and the mixed number is -4 1/24
4 0
2 years ago
Change each of the following points from rectangular coordinates to spherical coordinates and to cylindrical coordinates.
FromTheMoon [43]

Answer and Step-by-step explanation: Spherical coordinate describes a location of a point in space: one distance (ρ) and two angles (Ф,θ).To transform cartesian coordinates into spherical coordinates:

\rho = \sqrt{x^{2}+y^{2}+z^{2}}

\phi = cos^{-1}\frac{z}{\rho}

For angle θ:

  • If x > 0 and y > 0: \theta = tan^{-1}\frac{y}{x};
  • If x < 0: \theta = \pi + tan^{-1}\frac{y}{x};
  • If x > 0 and y < 0: \theta = 2\pi + tan^{-1}\frac{y}{x};

Calculating:

a) (4,2,-4)

\rho = \sqrt{4^{2}+2^{2}+(-4)^{2}} = 6

\phi = cos^{-1}(\frac{-4}{6})

\phi = cos^{-1}(\frac{-2}{3})

For θ, choose 1st option:

\theta = tan^{-1}(\frac{2}{4})

\theta = tan^{-1}(\frac{1}{2})

b) (0,8,15)

\rho = \sqrt{0^{2}+8^{2}+(15)^{2}} = 17

\phi = cos^{-1}(\frac{15}{17})

\theta = tan^{-1}\frac{y}{x}

The angle θ gives a tangent that doesn't exist. Analysing table of sine, cosine and tangent: θ = \frac{\pi}{2}

c) (√2,1,1)

\rho = \sqrt{(\sqrt{2} )^{2}+1^{2}+1^{2}} = 2

\phi = cos^{-1}(\frac{1}{2})

\phi = \frac{\pi}{3}

\theta = tan^{-1}\frac{1}{\sqrt{2} }

d) (−2√3,−2,3)

\rho = \sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}+3^{2}} = 5

\phi = cos^{-1}(\frac{3}{5})

Since x < 0, use 2nd option:

\theta = \pi + tan^{-1}\frac{1}{\sqrt{3} }

\theta = \pi + \frac{\pi}{6}

\theta = \frac{7\pi}{6}

Cilindrical coordinate describes a 3 dimension space: 2 distances (r and z) and 1 angle (θ). To express cartesian coordinates into cilindrical:

r=\sqrt{x^{2}+y^{2}}

Angle θ is the same as spherical coordinate;

z = z

Calculating:

a) (4,2,-4)

r=\sqrt{4^{2}+2^{2}} = \sqrt{20}

\theta = tan^{-1}\frac{1}{2}

z = -4

b) (0, 8, 15)

r=\sqrt{0^{2}+8^{2}} = 8

\theta = \frac{\pi}{2}

z = 15

c) (√2,1,1)

r=\sqrt{(\sqrt{2} )^{2}+1^{2}} = \sqrt{3}

\theta = \frac{\pi}{3}

z = 1

d) (−2√3,−2,3)

r=\sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}} = 4

\theta = \frac{7\pi}{6}

z = 3

5 0
3 years ago
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