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faltersainse [42]
3 years ago
15

Please help me, I will give you brainliest if it's right! <3 :)

Mathematics
1 answer:
stepladder [879]3 years ago
4 0

Answer:

-18

Step-by-step explanation:

-18

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Order the data from lest to greatest 35, 24,25,38,31,20,27
kolbaska11 [484]

Answer:

Step-by-step explanation:

20,24,25,27,31,35,38

minimum;20

medium: 27

maximum: 38

lower quartile: 24

upper quartile:35

put numbers in number order

the first number is the minimum, the last number is the maximum. the middle number "split" is the median.

quartiles are the numbers in the middle of the data you just "split"

(so like a quarter)

i may be wrong i haven't done this in years

3 0
3 years ago
PLEASE HELPP!!! (look at picture)
kow [346]

Answer: 7

Step by Step explanation:

4 0
3 years ago
What is the value of x and the length of segment DE?
natali 33 [55]

Answer:

x= 6.6     Length of DE= 16.2

Step-by-step explanation:

I got it right on edge

7 0
3 years ago
Find the area of the circle. Round your answer to the nearest tenth. The circle has a radius of 9
Rudik [331]

Answer:

I is at least ten because of nine it rounds to ten

3 0
3 years ago
Give the properties for the equation -2x 2 - y + 10x - 7 = 0.
Sladkaya [172]

Given:

The quadratic equation is

-2x^2-y+10x-7=0

To find:

The vertex of the given quadratic equation.

Solution:

If a quadratic function is f(x)=ax^2+bx+c, then

Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)

We have,

-2x^2-y+10x-7=0

It can be written as

-2x^2+10x-7=y

y=-2x^2+10x-7           ...(i)

Here, a=-2,b=10,c=-7.

\dfrac{-b}{2a}=\dfrac{-10}{2(-2)}

\dfrac{-b}{2a}=\dfrac{-10}{-4}

\dfrac{-b}{2a}=\dfrac{5}{2}

Putting x=\dfrac{5}{2} in (i), we get

y=-2(\dfrac{5}{2})^2+10(\dfrac{5}{2})-7

y=-2(\dfrac{25}{4})+\dfrac{50}{2}-7

y=\dfrac{-50}{4}+25-7

y=\dfrac{-25}{2}+18

On further simplification, we get

y=\dfrac{-25+36}{2}

y=\dfrac{11}{2}

So, the vertex of the given quadratic equation is \left(\dfrac{5}{2},\dfrac{11}{2}\right).

Therefore, the correct option is A.

3 0
3 years ago
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