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Serjik [45]
3 years ago
13

Which equation when graph has x intercepts at (2,0) and (4,0) and a y-intercept of (0,-16)?

Mathematics
2 answers:
julsineya [31]3 years ago
8 0
The correct answer is C. if you plug zero in for 'x' you will get the y-intercept.
-2(0-2)(0-4)= -2(-2)(-4)=-16
Next set each factor equal to zero to get the x-intercepts.
(x-2)=0 x = 2 (2,0)
(x-4) = 0 x = 4 (4,0)

I hope this helps
Neporo4naja [7]3 years ago
3 0

Answer:

The answer is C. on Edgenuty.

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4. The population of a small town is given by the function p=35t +1450, where t is the number
Elena-2011 [213]

Answer:

1625

Step-by-step explanation:

35(5) + 1450 = 1625

35 x 5 = 175

175 + 1450 = 1625

6 0
3 years ago
Which of the following represents h (x-2) + 3
fomenos

Answer:

A

Step-by-step explanation:

For transformation functions;

(x-2), the 2 represents horizontal shift (left or right)

if it is a positive= shift left

if it is a negative= shift right

since it is -2, the vertex of the graph is shifted right by 2 units.

For the +3 on the outside of h(x-2), this addresses the vertical shift.

Since it is +3, this means that the graph's vertex is shifted up.

8 0
3 years ago
If n + 7 = 10, evaluate 2n - 2
Vedmedyk [2.9K]
N=10-7

n=3

Now

2n-2

2*3-2

6-2

4
5 0
3 years ago
K = mv / 2 solve for m . HELP PLEASE HURRY!
Aleksandr-060686 [28]

9514 1404 393

Answer:

  m = 2k/v

Step-by-step explanation:

Identify the coefficient of m (v/2) and multiply by its inverse (2/v).

  (2/v)k = (2/v)m(v/2) . . . . multiply both sides of the equation by 2/v

  2k/v = m . . . simplify

  m = 2k/v

3 0
3 years ago
Find the x-intercepts of the parabola with vertex (-5,80) and y-intercept (0,-45). Write your answer in this form (x of 1 , y of
Ivan
A parabola is a quadratic function, and a quadratic can be expressed in vertex form, which is:

y=a(x-h)^2+k, where (h,k) is the vertex (absolute maximum or minimum point of the quadratic)

In this case we are given that (h,k) is (-5,80) so we have so far:

y=a(x--5)^2+80

y=a(x+5)^2+80, we are also told that it passes through the point (0,-45) so:

-45=a(0+5)^2+80

-45=25a+80  subtract 80 from both sides

-125=25a  divide both sides by 25

-5=a, so now we know the complete vertex form is:

y=-5(x+5)^2+80

The x-intercepts occur when y=0 so:

0=-5(x+5)^2+80  add 5(x+5)^2 to both sides

5(x+5)^2=80  divide both sides by 5

(x+5)^2=16  take the square root of both sides

x+5=±√16  which is

x+5=±4  subtract 5 from both sides

x=-5±4 so the x-intercepts are:

x=-1 and -9


7 0
4 years ago
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