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Serjik [45]
3 years ago
13

Which equation when graph has x intercepts at (2,0) and (4,0) and a y-intercept of (0,-16)?

Mathematics
2 answers:
julsineya [31]3 years ago
8 0
The correct answer is C. if you plug zero in for 'x' you will get the y-intercept.
-2(0-2)(0-4)= -2(-2)(-4)=-16
Next set each factor equal to zero to get the x-intercepts.
(x-2)=0 x = 2 (2,0)
(x-4) = 0 x = 4 (4,0)

I hope this helps
Neporo4naja [7]3 years ago
3 0

Answer:

The answer is C. on Edgenuty.

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Y= -3x+4   should be 0

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Find the missing coefficient.<br><br> -<br> y2 − [-5y − y(-7y − 9)] − [-y (15y + 4)] = 0
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There is only one solution in the given equation -y2 − [-5y − y(-7y − 9)] − [-y (15y + 4)] = 0. In solving this problem, apply first PEMDAS (parenthesis, exponents,multiplication, division, addition, subtraction). Then equation will transform into -y2+5y-7y2-9y+15y2+4y=0. Combine terms with same power and achieve 7y2=0. Divide both sides with 7 and perform square root of zero. Since the root is zero, we have one solution of the given equation which is y=0.
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Help please!! I will give crown! :D
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C. Please mark Brainliest!!!!!!

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6 0
3 years ago
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Given that u =&lt; 2,12 &gt;, and z =&lt; -7,5 &gt;
swat32

Using the dot product:

For any vector x, we have

||x|| = √(x • x)

This means that

||w|| = √(w • w)

… = √((u + z) • (u + z))

… = √((u • u) + (u • z) + (z • u) + (z • z))

… = √(||u||² + 2 (u • z) + ||z||²)

We have

u = ⟨2, 12⟩   ⇒   ||u|| = √(2² + 12²) = 2√37

z = ⟨-7, 5⟩   ⇒   ||z|| = √((-7)² + 5²) = √74

u • z = ⟨2, 12⟩ • ⟨-7, 5⟩ = -14 + 60 = 46

and so

||w|| = √((2√37)² + 2•46 + (√74)²)

… = √(4•37 + 2•46 + 74)

… = √314 ≈ 17.720

Alternatively, without mentioning the dot product,

w = u + z = ⟨2, 12⟩ + ⟨-7, 5⟩ = ⟨-5, 17⟩

and so

||w|| = √((-5)² + 17²) = √314 ≈ 17.720

7 0
2 years ago
Find the mean of the rainfall amounts .
anygoal [31]

Answer:

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