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3 years ago

5

Brainliest to who ever is correct

2 answers:

neonofarm [45]3 years ago

8 0

Answer: D i hope

Step-by-step explanation: your welcome

fenix001 [56]3 years ago

8 0

Answer:

i think guy above me is right

Step-by-step explanation:

You might be interested in

Plot the following points and find the area of the figure. (3,2); (-3,2); (-3,-3); (3,-3)

nevsk [136]

We have been given 4 points $(3,2), (-3,2), (-3,-3), (3,-3)$ . We are asked yo plot these points on coordinate plane and find the area of the figure.

Upon plotting our given points, we will get a rectangle as shown in the attached file.

We can see that the width is 5 units that is difference between y-coordinates of point $(3,2)\text{ and }(3,-3)$ .

$\text{Width}=2-(-3)=2+3=5$

We can see that the length of rectangle is 6 units that is difference between x-coordinates of point $(-3,2)\text{ and }(3,2)$ .

$\text{Length}=3-(-3)=3+3=6$

We know that area of rectangle is length times width.

$A=\text{Length}\times \text{Width}$

$A=6\times 5$

$A=30$

Therefore, the area of the figure would be 30 square units.

6 0

4 years ago

I need help plz and plz explain why plz

Mariana [72]

Answer:

156 minutes

Step-by-step explanation:

2 hrs=120 minutes

3/5 hr=3/5 *60=36 minutes

120+36=156 minutes

hope this helps

brainliest?

6 0

3 years ago

Read 2 more answers

1. What is the vertex form of the equation?

sergeinik [125]

1.vertex form is $y=a(x-h)^2+k$

to get into vertex form, complete the square

$y=-x^2+12x-4$

step 1: group x terms

$y=(-x^2+12x)-4$

step 2: factor coefient in front of x^2 term

$y=-1(x^2-12x)-4$

prep for next step: take 1/2 of linear (1st dgree term) and square it

$\frac{-12}{2}=-6$ , $(-6)^2=36$

step 3: add positive and negative of that previous number inside the parenthasees

$y=-1(x^2-12x+36-36)-4$

factor perfect squaer trionmial

$y=-1((x-6)^2-36)-4$

take out that -36 by expansion

$y=-1(x-6)^2+36-4$

$y=-1(x-6)^2+32$

2. factor out the 2

$2(x^2+8x+12)$

what 2 numbers multiply to get 12 and add to get 8?

2 and 6

$2(x+2)(x+6)$

3.

for $ax^2+bx+c=0$

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

in our case

$x^2-7x-6=0$

a=1, b=-7, c=-6

$x=\frac{-(-7) \pm \sqrt{(-7)^2-4(1)(-6)}}{2(1)}$

$x=\frac{7 \pm \sqrt{73}}{2}$

so $x=\frac{7+\sqrt{73}}{2}$ and $x=\frac{7-\sqrt{73}}{2}$

4. remember that $i=\sqrt{-1}$ so $i^2=-1$

treat $i$ as a variable

$(-2i)(8i)=$

$(-2)(i)(8)(i)=$

$(-2)(8)(i)(i)=$

$(-16)(i^2)=$

$(-16)(-1)=$

[tex}16[/tex]

8 0

3 years ago

Read 2 more answers

Factor completely: 4a^2+b^2−c^2+4ab

Lapatulllka [165]

Answer:

$4a^{2} + b^{2} - c^{2} + 4ab$ $= (2a + b -c) (2a + b+c)$

Step-by-step explanation:

Here, the given expression is $4a^{2} + b^{2} - c^{2} + 4ab$

or, the given expression can be written as

$(4a^{2} + b^{2} + 4ab ) - c^{2}$

Now, by ALGEBRAIC IDENTITY: $(x+y)^{2} = x^{2} + y^{2} + 2xy$

So, similarly here, $(2a +b){2} = 4a^{2} + b^{2} + 4ab$

Hence, on simplification, the expression

$(4a^{2} + b^{2} + 4ab ) - c^{2} = (2a + b)^{2} - c^{2}$

Now, by ALGEBRAIC IDENTITY: $(x +y)(x-y) = x^{2} - y^{2}$

So, similarly $(2a + b)^{2} - c^{2}$ $= (2a + b -c) (2a + b+c)$

Hence, the given expression is factorized as:

$4a^{2} + b^{2} - c^{2} + 4ab$ $= (2a + b -c) (2a + b+c)$

7 0

3 years ago

a machine packs boxes at a constant rate of 2/3 of a box every 1/2 minute what is the number of boxes per minute that mahine pac

mote1985 [20]

Answer:

3/5

Step-by-step explanation:

8 0

3 years ago