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VladimirAG [237]
2 years ago
9

Find the common ratio of the geometrie sequence -15, -30, -60, ...

Mathematics
1 answer:
andrew11 [14]2 years ago
4 0

Answer:

I think it's -15 I'm not 100% sure

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Draw and LABEL a picture to show how knowing 7+7 help you find 7+8
boyakko [2]
7+7 = 14 So knowing that 8 is only one more than 7+7 you can do 14 + 1 = 15 ..
4 0
3 years ago
50 POINTS 10 QUESTIONS! <br><br> Solve each quadratic equation using factoring<br><br> PLEASE HELP!!
Tanzania [10]

Answer:

Quadratic Equation | Factoring

Solve each quadratic equation using factoring.

1) v² + 5v + 6 = 0

doing middle term factorisation

v²+(3+2)v+6=0

v²+3v+2v+6=0

v(v+3)+2(v+3)=0

(v+3)(v+2)=0

either

<u>v=-3</u>

<u>or</u>

<u>v=-2</u>

2) g² - 3g = 4

keeping all terms in one side

g²-3g-4=0

doing middle term factorisation

g²-(4-1)g-4=0

g²-4g+g-4=0

g(g-4)+1(g-4)=0

(g-4)(g+1)=0

either

<u>g=4</u>

<u>or</u>

<u>g=-1</u>

3)w² + 4w = 0

w(w+4)=0

either

<u>w=0</u>

<u>or</u>

<u>w=-4</u>

4) s² - 8s + 12 = 0

doing middle term factorisation

s²-(6+2)+12=0

s²-6s-2s+12=0

s(s-6)-2(s-6)=0

(s-6)(s-2)=0

either

<u>s=6</u>

<u>or</u>

<u>s=2</u>

5) x ²+ 2x - 35 = 0

doing middle term factorisation

x²+(7-5)x-35=0

x²+7x-5x-35=0

x(x+7)-5(x+7)=0

(x+7)(x-5)=0

either

<u>x=-7</u>

<u>or</u>

<u>x=5</u>

6) r(r + 2) = 99

opening bracket

r²+2r=99

keeping all terms in one side

r²+2r-99=0

r²+(11-9)r-99=0

r²+11r-9r-99=0

r(r+11)-9(r+11)=0

(r+11)(r-9)=0

either

<u>r=-11</u>

<u>or</u>

<u>r=9</u>

7)k(k-4)=-3

opening bracket

k²-4k=-3

keeping all terms in one side

k²-4k+3=0

k²-(3+1)k+3=0

k²-3k-k+3=0

k(k-3)-1(k-3)=0

(k-3)(k-1)=0

either

k=3

or

k=1

8)t²+ 3t + 2 = 0

doing middle term factorisation

t²+(2+1)t+2=0

t²+2t+t+2=0

t(t+2)+1(t+2)=0

(t+2)(t+1)=0

either

<u>t</u><u>=</u><u>-</u><u>2</u>

<u>or</u>

<u>t</u><u>=</u><u>-</u><u>1</u>

9)m ^ 2 - 81 = 0

m²=81

doing square root in both side

\sqrt{m²}=\sqrt{9²}

<u>m=±9</u>

<u>either</u>

<u>m</u><u>=</u><u>9</u>

<u>or</u>

<u>m</u><u>=</u><u>-</u><u>9</u>

10) h²- 17h + 70 = 0

doing middle term factorisation

h²-(10+7)h+70=0

h²-10h-7h+70=0

h(h-10)-7(h-10)=0

(h-10)(h-7)=0

either

<u>h</u><u>=</u><u>1</u><u>0</u>

<u>or</u>

<u>h</u><u>=</u><u>7</u>

6 0
2 years ago
Read 2 more answers
Last question need to be answered
shepuryov [24]
The answer would be 110 degrees. 
4 0
3 years ago
Read 2 more answers
21x^5y^4-18x^7y^3+15x^2y^5
soldi70 [24.7K]

Do you want us to answer or simplify?

Simplify:=−18x^7  y^3 + 21x^5  y^4+ 15x^2 y^5

5 0
3 years ago
Write
IRISSAK [1]

Answer:

y = 2 ( x − 1 ) ^ 2 + 2

Step-by-step explanation:

y = a ( x − h ) ^ 2 + k

where vertex is (h,k) = (1,2)

h=1, k=2

y = a ( x − 1 ) ^ 2 + 2

sub ( 3,10)

10 = a (3 - 1)^2 + 2

a=2

y = 2 ( x − 1 ) ^ 2 + 2

7 0
2 years ago
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