Capillaries are one cell thick and so this makes them very thin. capillaries are also arranged in networks known as capillary beds, and thus multiple capillaries are spread over a large area.
Chloroplast is the cell structure that enables the process of photosynthesis
30. Assuming that meiosis was undergone without error, the daughter cells formed are haploid.
1. Mitosis takes place within somatic cells (cells that make up the body). Meiosis takes place within gamete cells (sex cells).
2. One single division of the mother cell results in two daughter cells. Two divisions of the mother cell result in four meiotic products or haploid gametes.
3. A mitotic mother cell can either be haploid or diploid. A meiotic mother cell is always diploid.
4. The number of chromosomes per nucleus remains the same after division. The meiotic products contain a haploid (n) number of chromosomes in contrast to the (2nd) number of chromosomes in the mother cell.
5. It is preceded by an S-phase in which the amount of DNA is duplicated. In meiosis, only meiosis I is preceded by an S-phase.
6. In mitosis, there is no pairing of homologous chromosomes. During prophase I, complete pairing of all homologous chromosomes takes place.
7. There is no exchange of DNA (crossing-over) between chromosomes. There is at least one crossing-over or DNA exchange per homologous pair of chromosomes.
8. The centromeres split during anaphase. The centromeres do separate during anaphase II, but not during anaphase I.
9. The genotype of the daughter cells is identical to that of the mother cells. Meiotic products differ in their genotype from the mother cell.
10. After mitosis, each daughter cell has exactly same DNA strands. After meiosis, each daughter cell has only half of the DNA strands
Answer:
t = ln (N/N°)/(-0.0239)
Explanation :
The decay law is represented as
N = N°e^-kt
Where N is the final number of atom,
N° is the initial number of atoms
k is the decay constant
t is the half-life.
From the above we have,
N/N° = e^-kt
take ln of both sides
ln (N/N°) = -kt
t = ln(N/N°)/-k
At half life, N/N° = 1/2
Therefore, t = (ln 1/2)/-k
t = -0.693/-k
But t = 29 sec
29 = -0.693/-k
k = 0.0239 s^-1
Therefore,
The formula will be
t = ln (N/N°)/(-0.0239)
