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kherson [118]
3 years ago
8

Mustafa is flying his kite, and Ana is watching from 20 m away, as shown. From Ana's perspective there is an

Mathematics
2 answers:
Maslowich3 years ago
8 0
7.80 because it’s is a number everyone know
victus00 [196]3 years ago
8 0

Answer: From Mustafa's perspective, there is a 47\degree47°47, degree angle between Ana and the kite.

Step-by-step explanation: Khan Academy

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Diane runs 10 miles in 55 minutes, how many minuets does she take per mile?
Brut [27]

Step-by-step explanation:

<em>Hi</em><em>!</em><em>!</em>

<em> </em><em>It's</em><em> </em><em>simple</em><em>, </em><em>you</em><em> </em><em>can</em><em> </em><em>do</em><em> </em><em>it</em><em> </em><em>easily</em><em>. </em>

<em>no</em><em>.</em><em> </em><em>of</em><em> </em><em>miles</em><em> </em><em>=</em><em> </em><em>1</em><em>0</em><em> </em><em>miles</em>

<em>time</em><em> </em><em>=</em><em> </em><em>5</em><em>5</em><em> </em><em>mins</em><em>.</em>

<em>now</em><em>,</em>

<em>n</em><em>o</em><em>.</em><em> </em><em>o</em><em>f</em><em> </em><em>m</em><em>i</em><em>n</em><em>s</em><em> </em><em>for</em><em> </em><em>1</em><em> </em><em>mile</em><em> </em><em>=</em><em> </em><em>no</em><em>.</em><em> </em><em>of</em><em> </em><em>miles</em><em>/</em><em> </em><em>time</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>1</em><em>0</em><em> </em><em>/</em><em>5</em><em>5</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>0</em><em>.</em><em>1</em><em>8</em><em>1</em><em>8</em><em>1</em><em>8</em><em>1</em><em>8</em><em> </em><em>min</em><em>.</em>

<em>so</em><em>,</em><em> </em><em>she</em><em> </em><em>takes</em><em> </em><em>0</em><em>.</em><em>1</em><em>8</em><em>1</em><em>8</em><em>1</em><em>8</em><em> </em><em>or</em><em> </em><em>2</em><em>/</em><em>1</em><em>1</em><em> </em><em>min</em><em> </em><em>per</em><em> </em><em>each</em><em> </em><em>mile</em><em>.</em>

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

5 0
3 years ago
Read 2 more answers
Someone solve this please like NOW 4(5x-7)+12=16x+24
Bingel [31]

20x-28+12=16x+24 (i distributed the 4 to get this)

20x-16=16x+24 (added -28 & 12)

4x=40 (Subtracted 16x from both sides and added 16 to both sides)

(divide by 4 on both sides)

x=10

7 0
3 years ago
What is Question I (if m&lt;EBF = 117°, fine m&lt;ABE)​
Natasha_Volkova [10]

Answer:

m∠ABE = 27°

Step-by-step explanation:

* Lets look to the figure to solve the problem

- AC is a line

- Ray BF intersects the line AC at B

- Ray BF ⊥ line AC

∴ ∠ABF and ∠CBF are right angles

∴ m∠ABF = m∠CBF = 90°

- Rays BE and BD intersect the line AC at B

∵ m∠ABE = m∠DBE ⇒ have same symbol on the figure

∴ BE is the bisector of angle ABD

∵ m∠EBF = 117°

∵ m∠EBF = m∠ABE + m∠ABF

∵ m∠ABF = 90°

∴ 117° = m∠ABE + 90°

- Subtract 90 from both sides

∴ m∠ABE = 27°

4 0
3 years ago
Read 2 more answers
The outer angle at the top C of the ABC is 112 °. If the bisector of the side AB intersects the side AC at point Q and the segme
Arisa [49]

Step-by-step explanation:

The outer angle at the top C of the ABC is 112 °. If the bisector of the side AB intersects the side AC at point Q and the segment BQ is perpendicular to AC, find the magnitude of ABC

3 0
2 years ago
14 = 2y/5 what is the solution?
Gnom [1K]

Answer:

y=35

Step-by-step explanation:

y in (-oo:+oo)

14 = (2*y)/5 // - (2*y)/5

14-((2*y)/5) = 0

(-2/5)*y+14 = 0

14-2/5*y = 0 // - 14

-2/5*y = -14 // : -2/5

y = -14/(-2/5)

y = 35

y = 35

5 0
3 years ago
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