Answer:
Angle I = 90 degrees
Angle J = 61 degrees
Angle K = 29 degrees
Step-by-step explanation:
Angle I is given
We know that the angles in all triangles add up to 180. Since we are given that angle I is equal to 90 degrees, we now know that angle J + angle K = 90 degrees:
(5x+26) + (2x+15) = 90
Solve for X:
7x + 41 = 90
7x = 49
x = 7
Angle J = (5x + 26) = (5(7) + 26) = 61
Angle K = (2x + 15) = (2(7) + 15) = 29
Checking your work: 61 + 29 = 90
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We know that According to Algebra of Real Functions :
If f and g are two real functions which are defined under the same domain then 

Now we need find the Domain of this Function :
The Condition for Square Root to be defined is any Expression under it should be Greater than or Equal to Zero.
When Function is a Fraction, it Cannot be defined when the denominator becomes zero. Because when the denominator is zero, the fraction tends to ∞ (because anything divided by zero tends to ∞)
According to Above Conditions Described above, The Given Function is Definable only when the Expression which is under the Square Root is Greater than Zero and x ≠ 0
⇒ 3x - 9 > 0
⇒ 3x > 9
⇒ x > 3
⇒ The Domain of the Given Function is (3 , ∞)
1st Option is the Answer
Answer:
C
Step-by-step explanation:
By tracing the figure, we see that we go around a semicricle twice and go in a straight path twice. So the perimeter of this figure consists of two semicircles and two line segments, hence the answer is C.
Answer:
The original number is 
Step-by-step explanation:
Let
x -----> the original number
Remember that

The increased number is equal to multiply the original number by the factor 1.071
so

Solve for x
Divide by 1.071 both sides
