In this case, we cannot simply take the average speed by
adding the two speeds and divide by two.
What we have to do is to calculate the time required
going to school and the return trip home.
We know that to calculate time, we use the formula:
t = d / v
where,
d = distance = 4.8 km = 4800 m
v = velocity
Let us say that the variables related to the trip going
to school is associated with 1, and the return trip home is 2. So,
t1 = 4800 m / (22.6 m / s)
t1 = 212.39 s
t2 = 4800 / (16.8 m / s)
t2 = 285.71 s
total time, t = t1 + t2
t = 498.1 s
Therefore the total average velocity is:
= (4800 m + 4800 m) / 498.1 s
= 19.27 m / s = 19.3 m / s
Answer:
19.3 m/s
Well, you could easily type that into a calculator, but the answer would be 0.04347826, but when you say it as an answer you say the answer up to the hundredths place, which would be 0.043. =)
Answer: Its 3 ^(x-2) + 2
Step-by-step explanation:
Because y increases when x increase base is 3. Try
x = 2 gives 3^(-1) + 2 = 2,33 and x = 3 gives 3^0 + 2 = 3
Answer:
The answer is the third selection
Step-by-step explanation:
Answer:
Step-by-step explanation:
