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Nata [24]
2 years ago
5

PLS HELP!!! ITS ALMOST DUE

Mathematics
1 answer:
seropon [69]2 years ago
6 0

Answer:

D

Step-by-step explanation:

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Round 217.72668318 to the nearest thousandth
Andrei [34K]

hi <3

as the value after the thousandth place is 6, you would need to round up

thus, your answer would be 217.727

hope this helps :)

8 0
2 years ago
Read 2 more answers
Solve the inequality -2(k+3) &lt; -2k - 7
ExtremeBDS [4]
This equation would be represented as a No Solution equation. Due to the fact that if you do inverse operation and combine like terms, your variables will cancel out.
8 0
3 years ago
17. Solve the problem (–13 – 5) – (8 + 2) = ? A. –18 B. –24 C. –28 D. –8
creativ13 [48]

(–13 – 5) – (8 + 2)

= - 18 - 10

= -28

Answer

C. –28

5 0
3 years ago
A camera manufacturer spends $2,000 each day for overhead expenses plus $9 per camera for labor and materials. The cameras sell
hjlf
A) let the number of cameras sold per day for breakeven be x

Total daily cost = 2000 + 9x

Total daily revenue = 17x

therefore for just covering expenses both cost and revenue must be equal

2000 + 9x = 17x

2000 = 17x - 9x = 8x

x = 2000/8 = 250 cameras


b) increasing production by 50 cameras per day will give a daily profit of;

50 * (17 - 9) = 50 * 8 = $400 (seeing that the fixed daily cost of $2000 remains unchanged)


It's a
6 0
3 years ago
The time it takes to completely tune an engine of an automobile follows an exponential distribution with a mean of 40 minutes.
Mazyrski [523]

Answer: a. P (x<30) = 0.5276

              b. P (30<x<35) = 0.0555

Step-by-step explanation: An <u>exponential</u> <u>distribution</u> is a distribution of time in which events happens at a constant average rate.

The rate is calculated as

\lambda=\frac{1}{\mu}

with μ as the mean.

The probability density distribution for this type of distribution is

f(x)=\lambda e^{-\lambda x}

And probability is calculated as

P(X

For tuning of an engine, the rate is

\lambda=\frac{1}{40}

λ = 0.025

a. Probability of less than 30 minutes:

P(X

P(X

P (X < 30) = 0.5276

<u>Probability of tuning in 30 minutes or less is </u><u>52.76%</u><u>.</u>

<u />

b. Probability of between 30 and 35 can be described as

P(30

P(X

P(X

P (X < 35) = 0.5831

P (X < 30) = 0.5276

Then:

P(30

P (30 < X < 35) = 0.0555

<u>Probability of tuning an engine between 30 and 35 minutes is </u><u>5.55%.</u>

<u />

<u />

5 0
2 years ago
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