Question

What is the surface area of the figure shown?

Answer 1

Answer:

The surface area is $404.8\ in^{2}$

Step-by-step explanation:

we know that

The surface area of the figure is equal to

$SA=2B+PL$

where

B is the area of the trapezoidal face

P is the perimeter of the trapezoidal face

L is the length of the figure

Find the area of B

$B=\frac{1}{2}(15+5)8\\ \\B=80\ in^{2}$

Find the perimeter P

$P=(8+5+12.8+15)=40.8\ in$

we have

$L=6\ in$

substitute the values

$SA=2(80)+(40.8)(6)=404.8\ in^{2}$