The bones of a mammal were discovered to have 3% as much Carbon-14 as they would have contained when
1 answer:
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Answer: See below
Step-by-step explanation:
The transformation from triangle LMN to triangle L'M'N' is the reflection about the line y =x.
The line segment from L to y=x and the line segment from L' to line y=x are congruent.
Yes, we will get the same characteristic if we draw a line from point M to y=x and the line from M' to y=x.
It is because points P', M' and N' are reflections of points P, M, and N respectively about the line y=x.
Graph 1 (attached as first picture)
Graphing a triangle LMN and reflecting it over the line y = x to create triangle L'M'N, we have:
The transformation from triangle LMN to triangle L'M'N' is the reflection about the line y =x.
Drawing a line from point L to the line y=x and from line L' to line y=x we have:
Graph 2 (attached as second picture)
The line segment from L to y=x and the line segment from L' to line y=x are congruent.
Yes, we will get the same characteristic if we draw a line from point M to y=x and the line from M' to y=x.
It is because points P', M' and N' are reflections of points P, M, and N respectively about the line y=x.
Option B: (b-a)/(b+a) is the correct answer
Step-by-step explanation:
The given expression is;
First of all we have to take LCM in both numerator and denominator
So,
The reciprocal of the denominator will be multiplied with the numerator for simplification
So,
Hence,
Option B: (b-a)/(b+a) is the correct answer
Keywords: Fractions, expressions
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Full Question:
<em>Tony rounded each of the numbers 1,143 and 1,149 to the nearest hundred. Which choice correctly compares the rounded numbers? </em>
<em></em>
Answer:
Step-by-step explanation:
Given
1,143 and 1,149
Required
Which of the option is correct
We start by approximating both numbers to nearest digit
<em>1,143; when approximated to nearest hundred is 1,100</em>
<em>1,149; when approximated to nearest hundred is also 1,100</em>
Hence;
1,143 ≅ 1,100
1,149 ≅ 1,100
Comparing both results, we have that
From the list of given options, option C is correct;