They want me to put something here and the question is the picture
1 answer:
Answer:
D. (1, -2)
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define systems</u>
5x - 2y = 9
3x + 4y = -5
<u>Step 2: Rewrite systems</u>
10x - 4y = 18
3x + 4y = -5
<u>Step 3: Solve for </u><em><u>x</u></em>
- Add to equations together: 13x = 13
- Divide 13 on both sides: x = 1
<u>Step 4: Solve for </u><em><u>y</u></em>
- Define: 3x + 4y = -5
- Substitute in <em>x</em>: 3(1) + 4y = -5
- Multiply: 3 + 4y = -5
- Isolate <em>y </em>term: 4y = -8
- Isolate <em>y</em>: y = -2
And we have our final answer!
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the square root of 1620
Step-by-step explanation:
1. x^2=18^2+36^2
2. x^2=324+1296
3. x^2=1620
4. x= The square root of 1620
Area = side AB * side BC = (5x + 5x + 3)(3x + 92x - 4)
= (10x + 3)(95x - 4) = 950x^2 - 40x + 285x - 12
= 950x^2 + 245x - 12 Answer
This cannot be negative so restriction on x is 950x^2 + 245x > 12
That is x > 0.0421
Answer:
x=8
Step-by-step explanation:
firstly take 30+18 which equals 48 and then divide that by six which will give you 8 as your answer