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2 years ago

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How to represent 7/3 on number line

1 answer:

MrMuchimi2 years ago

6 0

Answer:

u r ANS

Step-by-step explanation:

7/3 on number line

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How many students can sit around a cluster of 7 square table? The tables in a classroom have square tops. Four students can comf

Sveta_85 [38]

Answer:

16 students can sit around a cluster of 7 square table.

Step-by-step explanation:

Consider the provided information.

We need to find how many students can sit around a cluster of 7 square table.

The tables in a classroom have square tops.

Four students can comfortably sit at each table with ample working space.

If we put the tables together in cluster it will look as shown in figure.

From the pattern we can observe that:

Number of square table in each cluster Total number of students

1 4

2 6

3 8

4 10

5 12

6 14

7 16

Hence, 16 students can sit around a cluster of 7 square table.

8 0

3 years ago

Read 2 more answers

Find the point (,) on the curve =8 that is closest to the point (3,0). [To do this, first find the distance function between (,)

ELEN [110]

Question:

Find the point (,) on the curve $y = \sqrt x$ that is closest to the point (3,0).

[To do this, first find the distance function between (,) and (3,0) and minimize it.]

Answer:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

Step-by-step explanation:

$y = \sqrt x$ can be represented as: $(x,y)$

Substitute $\sqrt x$ for $y$

$(x,y) = (x,\sqrt x)$

So, next:

Calculate the distance between $(x,\sqrt x)$ and $(3,0)$

Distance is calculated as:

$d = \sqrt{(x_1-x_2)^2 + (y_1 - y_2)^2}$

So:

$d = \sqrt{(x-3)^2 + (\sqrt x - 0)^2}$

$d = \sqrt{(x-3)^2 + (\sqrt x)^2}$

Evaluate all exponents

$d = \sqrt{x^2 - 6x +9 + x}$

Rewrite as:

$d = \sqrt{x^2 + x- 6x +9 }$

$d = \sqrt{x^2 - 5x +9 }$

Differentiate using chain rule:

Let

$u = x^2 - 5x +9$

$\frac{du}{dx} = 2x - 5$

So:

$d = \sqrt u$

$d = u^\frac{1}{2}$

$\frac{dd}{du} = \frac{1}{2}u^{-\frac{1}{2}}$

Chain Rule:

$d' = \frac{du}{dx} * \frac{dd}{du}$

$d' = (2x-5) * \frac{1}{2}u^{-\frac{1}{2}}$

$d' = (2x - 5) * \frac{1}{2u^{\frac{1}{2}}}$

$d' = \frac{2x - 5}{2\sqrt u}$

Substitute: $u = x^2 - 5x +9$

$d' = \frac{2x - 5}{2\sqrt{x^2 - 5x + 9}}$

Next, is to minimize (by equating d' to 0)

$\frac{2x - 5}{2\sqrt{x^2 - 5x + 9}} = 0$

Cross Multiply

$2x - 5 = 0$

Solve for x

$2x =5$

$x = \frac{5}{2}$

Substitute $x = \frac{5}{2}$ in $y = \sqrt x$

$y = \sqrt{\frac{5}{2}}$

Split

$y = \frac{\sqrt 5}{\sqrt 2}$

Rationalize

$y = \frac{\sqrt 5}{\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$y = \frac{\sqrt {10}}{\sqrt 4}$

$y = \frac{\sqrt {10}}{2}$

Hence:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

3 0

3 years ago

Simplify (-2x3)2 · y · y9.<br><br> A) -4x6y8<br><br> B) -4x4y8<br><br> C) 4x6y10<br><br> D) -4x4y10

Alexxandr [17]

Answer:

Step-by-step explanation:

4 0

2 years ago

The architects side view drawing of a saltbox-style house shows a post that supports the roof ridge. The support post is 10 ft t

pochemuha

These calculations are based on the drawing of the file enclosed.

There are three right triangles.

From the big right triangle:

a^2 + b^2 = 25^2

From the small right triangle on the left side:

(25-x)^2 + 10^2 = a^2

From the small right triangle on the right side

x^2 +10^2 = b^2

=> (25-x)^2 + 10^2 + x^2 + 10^2 = a^2 + b^2

=> (25-x)^2 + 10^2 + x^2 + 10^2 = 25^2

=> 25^2 - 50x + x^2 + 10^2 + 10^2 = 25^2

=> x^2 -50x + 100 =0

Use the quadratic formular to find the roots:

x = 2.1 and x = 47.9

Distance from back: 25 - 2.1 = 22.9 ft

Answer: 22.9 ft

8 0

3 years ago

Read 2 more answers

Ayuda mee no like fr m

den301095 [7]

Answer:

I believe its option c 6

Step-by-step explanation:

in the chart, 6 is the smallest number started on

4 0

2 years ago