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3 years ago

Can someone help solve

Mathematics

1 answer:

leva [86]3 years ago

8 0

$\frac{-18z^{7}y^{5}-9z^{9}y^4+18z^6y^8}{9zy^{2} }= -2z^6y^3-z^8y^2+2z^5y^6$

When variables with exponents are divided by each other, you subtract the exponents.

For example:

$\frac{x^2}{x^1} = x^{2-1} =x^1$

$\frac{x^5}{x^3} =x^{5-3} = x^2$

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A triangle weighs 3 grams, and a circle weighs 6 grams. Use this applet to help find the weight of a square.

lesya [120]

Answer: 3.75 g

Step-by-step explanation:

Assume the weight of the square is x.

The hanger is in balance so the left side is equal to the right side.

Equation therefore is:

Triangle + Square + 3 * circle = 5* square + circle

3 + x + (3 * 6) = 5x + 6

3 + x + 18 = 5x + 6

5x - x = 3 + 18 - 6

4x = 15

x = 15/4

x = 3.75 g

7 0

2 years ago

Complete the comparison: 3 + 7 > ? A. 8 + 2 B. 10 − 2 C. 7 + 3 D. 9 + 4

Dafna1 [17]

3 + 7 > 10 - 2
10 > 8...correct

5 0

3 years ago

How to find the total surface area of a rectangular prism?

k0ka [10]

If the length is taken as l , height is taken as h and breadth is taken as b . then

Area of the rectangular prism= 2( (l*b) + (b*h) + (h*l) )

hope that helps

3 0

3 years ago

What is the decimal equivalent of the fraction?

Anton [14]

7 divided by 12 = 0.583

7 0

3 years ago

Read 2 more answers

Match the solid figure to the appropriate formula.

AlekseyPX

1. $L \cdot A=\pi r l$ - Cone

2. $V=\frac{4}{3} \pi r^{3}$ - Sphere

3. $T \cdot A=2 \pi r h+2 \pi r^{2}$ - Cylinder

4. $V=\frac{1}{3} B h$ - Pyramid

5. $L . A=p h$ - Prism

Solution:

1. $L \cdot A=\pi r l$

Lateral surface area of cone = $\pi r l$

where r is the radius of the cone and l is the slant height of the cone.

2. $V=\frac{4}{3} \pi r^{3}$

Volume of sphere = $\frac{4}{3} \pi r^{3}$

where r is the radius of the sphere.

3. $T \cdot A=2 \pi r h+2 \pi r^{2}$

Total surface area of cylinder = $2 \pi r h+2 \pi r^{2}$

where r is the radius of the cylinder and h is the height of the cylinder.

4. $V=\frac{1}{3} B h$

Volume of pyramid = $\frac{1}{3} B h$

where B is the base area of the pyramid and h is the height of the pyramid.

5. $L . A=p h$

Lateral surface area of prism = $p h$

where p is the perimeter of the base and h is the height of the prism.

4 0

3 years ago