Answer:
Small flags = 108
large flags= 47
Step-by-step explanation:
Step one:
given
let the number of small lag be x
and big flags be y
so
3.5x+6.5y= 683.5----------1
x+y=155------------------------2
Step two:
from eqn 2 x= 155-y
put x= 155-y in eqn 1
3.5(155-y)+6.5y= 683.5
542.5-3.5y+6.5y=683.5
collect like terms
3y=141
divide by 3
y= 141/3
y=47
Step three:
put y= 47 in eqn 2
x+47=155
x= 155-47
x=108
The answer is 50. I have the same question and it makes no sense. The r= and the d= are supposed to have answers, but I’m not sure how you get them
Answer:
Step-by-step explanation:
Apply rule : 
Apply rule : 
The value of the function 4g+ (3h-4j) is 34.
<h3>How to calculate the value?</h3>
It should be noted that the function that is given is illustrated as:
4g+ (3h-4j)
h = 10
g = 6
j = 5
We will put the values into the expression. This will be
4g+ (3h-4j)
= 4(6) + 3(10) - 4(5)
= 24 + 30 - 20
= 34
Therefore, the value of the function 4g+ (3h-4j) is 34.
Learn more about function on:
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Answer:
a=1
Step-by-step explanation:
To make this easier, combine like terms first.
-5+2a=4a-4-3a
-5+2a=a-4
Then, add 5 on both sides.
-5+2a=a-4
<u>+5 +5</u>
2a=a+1
Now, subtract a on both sides.
2a=a+1
<u>-a -a</u>
a=1
Hope this helps you out!!!! Have an amazing day :3
