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Irina18 [472]
3 years ago
8

B is the midpoint of ac. if ab=8x-7 bc=6x+7 find ac

Mathematics
1 answer:
quester [9]3 years ago
6 0

Answer: AC = 98

Step-by-step explanation:

A midpoint is a point on a line segment that divides it into <em>two equal parts</em>.

This means AB = BC

AB = 8x - 7

BC = 6x + 7

AB = BC

8x - 7 = 6x + 7

Solve this to find x

Add 7 to both sides

8x = 6x + 14

Subtract 6x from both sides

2x = 14

Divide both sides by 2

x = 7

Now AC = AB + BC

AC = AB + BC

AC = 8x - 7 + 6x + 7

AC = 14x

Substitute 7 for x

AC = 14(7)

AC = 98

Hope this helps!

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The U.S. Bureau of Economic Statistics reports that the average annual salary in the metropolitan Boston area is $50,542. Suppos
xenn [34]

Answer:

(a) P(X > $57,000) = 0.0643

(b) P(X < $46,000) = 0.1423

(c) P(X > $40,000) = 0.0066

(d) P($45,000 < X < $54,000) = 0.6959

Step-by-step explanation:

We are given that U.S. Bureau of Economic Statistics reports that the average annual salary in the metropolitan Boston area is $50,542.

Suppose annual salaries in the metropolitan Boston area are normally distributed with a standard deviation of $4,246.

<em>Let X = annual salaries in the metropolitan Boston area</em>

SO, X ~ Normal(\mu=$50,542,\sigma^{2} = $4,246^{2})

The z-score probability distribution for normal distribution is given by;

                      Z  =  \frac{X-\mu}{\sigma }  ~ N(0,1)

where, \mu = average annual salary in the Boston area = $50,542

            \sigma = standard deviation = $4,246

(a) Probability that the worker’s annual salary is more than $57,000 is given by = P(X > $57,000)

    P(X > $57,000) = P( \frac{X-\mu}{\sigma } > \frac{57,000-50,542}{4,246 } ) = P(Z > 1.52) = 1 - P(Z \leq 1.52)

                                                                     = 1 - 0.93574 = <u>0.0643</u>

<em>The above probability is calculated by looking at the value of x = 1.52 in the z table which gave an area of 0.93574</em>.

(b) Probability that the worker’s annual salary is less than $46,000 is given by = P(X < $46,000)

    P(X < $46,000) = P( \frac{X-\mu}{\sigma } < \frac{46,000-50,542}{4,246 } ) = P(Z < -1.07) = 1 - P(Z \leq 1.07)

                                                                     = 1 - 0.85769 = <u>0.1423</u>

<em>The above probability is calculated by looking at the value of x = 1.07 in the z table which gave an area of 0.85769</em>.

(c) Probability that the worker’s annual salary is more than $40,000 is given by = P(X > $40,000)

    P(X > $40,000) = P( \frac{X-\mu}{\sigma } > \frac{40,000-50,542}{4,246 } ) = P(Z > -2.48) = P(Z < 2.48)

                                                                     = 1 - 0.99343 = <u>0.0066</u>

<em>The above probability is calculated by looking at the value of x = 2.48 in the z table which gave an area of 0.99343</em>.

(d) Probability that the worker’s annual salary is between $45,000 and $54,000 is given by = P($45,000 < X < $54,000)

    P($45,000 < X < $54,000) = P(X < $54,000) - P(X \leq $45,000)

    P(X < $54,000) = P( \frac{X-\mu}{\sigma } < \frac{54,000-50,542}{4,246 } ) = P(Z < 0.81) = 0.79103

    P(X \leq $45,000) = P( \frac{X-\mu}{\sigma } \leq \frac{45,000-50,542}{4,246 } ) = P(Z \leq -1.31) = 1 - P(Z < 1.31)

                                                                      = 1 - 0.90490 = 0.0951

<em>The above probability is calculated by looking at the value of x = 0.81 and x = 1.31 in the z table which gave an area of 0.79103 and 0.9049 respectively</em>.

Therefore, P($45,000 < X < $54,000) = 0.79103 - 0.0951 = <u>0.6959</u>

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3 years ago
Write each fraction as the sum of a whole number and a fraction less than 1
Tpy6a [65]

Given:

The fractions are:

\dfrac{6}{5},\dfrac{11}{7},\dfrac{21}{4}

To find:

The each fraction as the sum of a whole number and a fraction less than 1.

Solution:

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\dfrac{6}{5}=\dfrac{5}{5}+\dfrac{1}{5}

\dfrac{6}{5}=1+\dfrac{1}{5}

Therefore, the given fraction \dfrac{6}{5} can be written as 1+\dfrac{1}{5}.

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Therefore, the given fraction \dfrac{11}{7} can be written as 1+\dfrac{4}{7}.

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\dfrac{21}{4}=\dfrac{20+1}{4}

\dfrac{21}{4}=\dfrac{20}{4}+\dfrac{1}{4}

\dfrac{21}{4}=5+\dfrac{1}{4}

Therefore, the given fraction \dfrac{21}{4} can be written as 5+\dfrac{1}{4}.

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