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3 years ago

(7 - 3t) + 3(-2t + 5)

Mathematics

2 answers:

tankabanditka [31]3 years ago

7 0

Answer:

22 - 9t

Step-by-step explanation:

(7 - 3t) + 3(-2t + 5)

7 - 3t + -6t + 15

7 - 9t + 15

22 - 9t

katrin2010 [14]3 years ago

6 0

Answer:

22-9t

Step-by-step explanation:

(7 - 3t) + 3(-2t + 5)

7+−3t+(3)(−2t)+(3)(5)=

7+−3t+−6t+15

Now you need to combine like terms.

7+−3t+−6t+15

(−3t+−6t)+(7+15)=

-9t+22=

22-9t

There you go.

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2 years ago

For 0 ≤ ϴ < 2π, how many solutions are there to tan(StartFraction theta Over 2 EndFraction) = sin(ϴ)? Note: Do not include va

Black_prince [1.1K]

Answer:

3 solutions:

$\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}$

Step-by-step explanation:

So, first of all, we need to figure the angles that cannot be included in our answers out. The only function in the equation that isn't defined for some angles is $tan(\frac{\theta}{2})$ so let's focus on that part of the equation first.

We know that:

$tan(\frac{\theta}{2})=\frac{sin(\frac{\theta}{2})}{cos(\frac{\theta}{2})}$

therefore:

$cos(\frac{\theta}{2})\neq0$

so we need to find the angles that will make the cos function equal to zero. So we get:

$cos(\frac{\theta}{2})=0$

$\frac{\theta}{2}=cos^{-1}(0)$

$\frac{\theta}{2}=\frac{\pi}{2}+\pi n$

$\theta=\pi+2\pi n$

we can now start plugging values in for n:

$\theta=\pi+2\pi (0)=\pi$

if we plugged any value greater than 0, we would end up with an angle that is greater than $2\pi$ so, that's the only angle we cannot include in our answer set, so: