Answer:
A and C
Step-by-step explanation:
Answer with explanation:
→→→Function 1
f(x)= - x²+ 8 x -15
Differentiating once , to obtain Maximum or minimum of the function
f'(x)= - 2 x + 8
Put,f'(x)=0
-2 x+ 8=0
2 x=8
Dividing both sides by , 2, we get
x=4
Double differentiating the function
f"(x)= -2, which is negative.
Showing that function attains maximum at ,x=4.
Now,f(4)=-4²+ 8× 4-15
= -16 +32 -15
= -31 +32
=1
→→→Function 2:
f(x) = −x² + 2 x − 3
Differentiating once , to obtain Maximum or minimum of the function
f'(x)= -2 x +2
Put,f'(x)=0
-2 x +2=0
2 x=2
Dividing both sides by , 2, we get
x=1
Double differentiating the function,gives
f"(x)= -2 ,which is negative.
Showing that function attains maximum at ,x=1.
f(1)= -1²+2 ×1 -3
= -1 +2 -3
= -4 +2
= -2
⇒⇒⇒Function 1 has the larger maximum.
X= 1/2 or x = 3/2.
Step 1: factor left side of equation. (2x-1)(2x-3)=O
Step 2: Set factors equal to 0. 2x-1=0 or 2x-3=0
X= 1/2 or x = 3/2.
Step 1: 0.282 = 282⁄1000
Step 2: Simplify 282⁄1000= 141⁄500
Answer:
Line segment JK
because the order of the letters matter when specifying congruent shapes.
