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Verizon [17]
3 years ago
10

A shark was swimming at 300 feet below sea level. He swam 300 feet up toward the surface. How many feet above sea level is the s

hark now?
Mathematics
1 answer:
Rom4ik [11]3 years ago
3 0

Answer: the shark is at sea level

Step-by-step explanation: is you are 300 beneath the sea level that's -300 and if you go up 300 ft that +300. So 300+(-300) gives you 0 making the shark at sea level.

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Justice league by murder
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7.60. When Paul crossed the finish line of a 60-meter race, he was ahead of Robert by 10 meters and ahead of Sam by 20 meters. S
Lelechka [254]

Answer:

The number of meters Robert will beat Sam is 12 meters.

Step-by-step explanation:

Given:

When Paul crossed the finish line of a 60-meter race, he was ahead of Robert by 10 meters and ahead of Sam by 20 meters. Suppose Robert and Sam continue to race to the finish line without changing their rates of speed.

Find:

the number of meters by which Robert will beat Sam

Step 1 of 1

When Paul finishes, Robert has run 60-10=50 meters and Sam has run 60-20=40 meters.

Therefore, when Robert and Sam run for the same amount of time, Sam covers $\frac{40}{50}=\frac{4}{5}$ of the distance that Robert covers. So, while Robert runs the final 10 meters of the race, Sam runs $\frac{4}{5} \cdot 10=8$ meters.

This means Robert's lead over Sam increases by 2 more meters, and he beats Sam by 10+2=12 meters.

5 0
1 year ago
anu borrows 12,500 as 12% per annum for 3 years at simple interest find the simple interest she has to pay at the end of 3 years
marishachu [46]

Answer:

The interest is 4,500

Step-by-step explanation:

We use the simple interest formula,

I = Prt

where

I = interest

P = principal amount = 12,500

r = interest rate = 12% = 0.12

t = time = 3 years

I = Prt

I = 12,500 × 0.12 × 3

I = 4,500

3 0
2 years ago
I want a tutor can I have some one help me
jekas [21]

Answer:

If you want add me on discord >>> fun54658#0871

7 0
3 years ago
Read 2 more answers
Test the series for convergence or divergence (using ratio test)​
Triss [41]

Answer:

    \lim_{n \to \infty} U_n =0

Given series is convergence by using Leibnitz's rule

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given series is an alternating series

∑(-1)^{n} \frac{n^{2} }{n^{3}+3 }

Let   U_{n} = (-1)^{n} \frac{n^{2} }{n^{3}+3 }

By using Leibnitz's rule

   U_{n} - U_{n-1} = \frac{n^{2} }{n^{3} +3} - \frac{(n-1)^{2} }{(n-1)^{3}+3 }

 U_{n} - U_{n-1} = \frac{n^{2}(n-1)^{3} +3)-(n-1)^{2} (n^{3} +3) }{(n^{3} +3)(n-1)^{3} +3)}

Uₙ-Uₙ₋₁ <0

<u><em>Step(ii):-</em></u>

    \lim_{n \to \infty} U_n =  \lim_{n \to \infty}\frac{n^{2} }{n^{3}+3 }

                       =  \lim_{n \to \infty}\frac{n^{2} }{n^{3}(1+\frac{3}{n^{3} } ) }

                    = =  \lim_{n \to \infty}\frac{1 }{n(1+\frac{3}{n^{3} } ) }

                       =\frac{1}{infinite }

                     =0

    \lim_{n \to \infty} U_n =0

∴ Given series is converges

                       

                     

 

3 0
2 years ago
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