The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation

Help please! which of the following represents two dependent events .

AveGali [126]

Answer:

i would say A

Step-by-step explanation:

4 0

2 years ago

The sum of two numbers is 35. There times the larger number is the same as 4 times the smaller number. Find the larger number. W

marshall27 [118]

35 = x + 4 -4
31 = x

4 0

3 years ago

WHOEVER GETS RIGHT GETS BRAINLIEST!!

ozzi

Answer:

Answer B: min. value at -6

Step-by-step explanation:

Complete the square of f(x) = x^2 - 2x - 5.

Note: Please use " ^ " to denote exponentiation, as shown.

Start with f(x) = x^2 - 2x - 5.

Identify the coefficient of the x term: it is 2.

Take half of that and square your result: (1/2)(2) = 1, and then 1^2 = 1.

Add and subtract this 1 between the 2x term and the constant term:

f(x) = x^2 - 2x + 1 - 1 - 5

Rewrite x^2 - 2x + 1 as a perfect square:

f(x) = (x - 1)^2 - 1 - 5, or f(x) = (x - 1)^2 - 6

Compare this to the standard form

f(x) = (x - h)^2 + k

We see that h = 1 and k = -6.

The vertex is located at (h, k); here, it's located at (1, -6).

Thus, the minimum value of this function is at the vertex (1, -6).

This agrees with Answer B: min. value at -6.

3 0

3 years ago

What is -3(-6+8)^3-2(1-3)^3

marin [14]

Assignment: $\bold{Solve \ Equation: \ -3\left(-6+8\right)^3-2\left(1-3\right)^3}$

<><><><><>

Answer: $\boxed{\bold{-8}}$

<><><><><>

Explanation: $\downarrow\downarrow\downarrow$

<><><><><>

[ Step One ] Follow PEMDAS Order Of Operations; Calculate Within Parenthesis

Note: $\bold{PEMDAS: \ Parenthesis, \ Exponents, \ Multiply, \ Divide, \ Add, \ Subtract}$

$\bold{-6+8: \ 2}$

[ Step Two ] Rewrite Equation

$\bold{-3\cdot \:2^3-2\left(1-3\right)^3}$

[ Step Three ] Calculate Within Parenthesis

$\bold{1-3: \ -2}$

[ Step Four ] Rewrite Equation

$\bold{-3\cdot \:2^3-2\left(-2\right)^3}$

[ Step Five ] Calculate Exponents

$\bold{2^3: \ 8}$

[ Step Six ] Rewrite Equation

$\bold{-3\cdot \:8-2\left(-8\right)}$

[ Step Seven ] Multiply

$\bold{2\left(-8\right): \ -16}$

[ Step Eight ] Rewrite Equation

$\bold{-24-\left(-16\right)}$

[ Step Nine ] Subtract

$\bold{-24-\left(-16\right): \ -8}$

[ Step Ten ] Rewrite Equation

$\bold{-8}$

<><><><><><><>

$\bold{\rightarrow Mordancy \leftarrow}$

8 0

3 years ago

In right ABC, AN is the altitude to the hypotenuse. FindBN, AN, and AC,if AB =2 5 in, and NC= 1 in.

Rama09 [41]

From the statement of the problem, we have:

• a right triangle △ABC,

,

• the altitude to the hypotenuse is denoted AN,

,

• AB = 2√5 in,

,

• NC = 1 in.

Using the data above, we draw the following diagram:

We must compute BN, AN and AC.

To solve this problem, we will use Pitagoras Theorem, which states that:

$h^2=a^2+b^2\text{.}$

Where h is the hypotenuse, a and b the sides of a right triangle.

(I) From the picture, we see that we have two sub right triangles:

1) △ANC with sides:

• h = AC,

,

• a = ,NC = 1,,

,

• b = NA.

2) △ANB with sides:

• h = ,AB = 2√5,,

,

• a = BN,

,

• b = NA,

Replacing the data of the triangles in Pitagoras, Theorem, we get the following equations:

$\begin{cases}AC^2=1^2+NA^2, \\ (2\sqrt[]{5})^2=BN^2+NA^2\text{.}\end{cases}\Rightarrow\begin{cases}NA^2=AC^2-1, \\ NA^2=20-BN^2\text{.}\end{cases}$

Equalling the last two equations, we have:

$\begin{gathered} AC^2-1=20-BN^2.^{} \\ AC^2=21-BN^2\text{.} \end{gathered}$

(II) To find the values of AC and BN we need another equation. We find that equation applying the Pigatoras Theorem to the sides of the bigger right triangle:

3) △ABC has sides:

• h = BC = ,BN + 1,,

,

• a = AC,

,

• b = ,AB = 2√5,,

Replacing these data in Pitagoras Theorem, we have:

$\begin{gathered} \mleft(BN+1\mright)^2=(2\sqrt[]{5})^2+AC^2 \\ (BN+1)^2=20+AC^2, \\ AC^2=(BN+1)^2-20. \end{gathered}$

Equalling the last equation to the one from (I), we have:

$\begin{gathered} 21-BN^2=(BN+1)^2-20, \\ 21-BN^2=BN^2+2BN+1-20 \\ 2BN^2+2BN-40=0, \\ BN^2+BN-20=0. \end{gathered}$

(III) Solving for BN the last quadratic equation, we get two values:

$\begin{gathered} BN=4, \\ BN=-5. \end{gathered}$

Because BN is a length, we must discard the negative value. So we have:

$BN=4.$

Replacing this value in the equation for AC, we get:

$\begin{gathered} AC^2=21-4^2, \\ AC^2=5, \\ AC=\sqrt[]{5}. \end{gathered}$

Finally, replacing the value of AC in the equation of NA, we get:

$\begin{gathered} NA^2=(\sqrt[]{5})^2-1, \\ NA^2=5-1, \\ NA=\sqrt[]{4}, \\ AN=NA=2. \end{gathered}$

Answers

The lengths of the sides are:

• BN = 4 in,

,

• AN = 2 in,

,

• AC = √5 in.

7 0

1 year ago