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Tom [10]
3 years ago
8

Exercises

Mathematics
1 answer:
zalisa [80]3 years ago
6 0

Answer:

$500,000

Step-by-step explanation:

5,000,000 x .1

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Find the sum of the infinite geometric series: 9 – 6 + 4 – …
balandron [24]
The defining characteristic of all geometric sequences is a common ratio which is a constant when dividing any term by the term preceding it.

In this case the common ratio is:  -6/9=4/-6=r=-2/3

An infinite series will have a sum when r^2<1, so in this case the sum will converge to an actual value because (-2/3)^(+oo) approaches zero.

The sum of any geometric sequence is:

s(n)=a(1-r^n)/(1-r), since we have a common ratio of -2/3 and we want to calculate an infinite series, ie, n approaches infinity, the sum becomes simply:

s(n)=a/(1-r)    (because (1-r^+oo) approaches 1 as n approaches +oo)

So our infinite sum is:

s(+oo)=9/(1--2/3)

s(+oo)=9/(1+2/3)

s(+oo)=9/(5/3)

s(+oo)=27/5

s(+oo)=54/10

s(+oo)=5.4
7 0
4 years ago
What is the awnser to 6 x 17?
Semmy [17]

the answer to 6×7 is equal to 102

7 0
3 years ago
Read 2 more answers
Solve the equation 5x+9 - x= 13 (use combine like term first)
Sophie [7]

Answer:

x=1

Step-by-step explanation:

5x+9 - x= 13

Combine like terms

4x +9 = 13

Subtract 9 from each side

4x+9-9 = 13-9

4x = 4

Divide each side by 4

4x/4 = 4/4

x=1

5 0
3 years ago
Read 2 more answers
Solve for F.<br> 3(6-f)-4=3f-4
Alinara [238K]

Answer:

F=3

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3(6−f)−4=3f−4

(3)(6)+(3)(−f)+−4=3f+−4(Distribute)

18+−3f+−4=3f+−4

(−3f)+(18+−4)=3f−4(Combine Like Terms)

−3f+14=3f−4

−3f+14=3f−4

Step 2: Subtract 3f from both sides.

−3f+14−3f=3f−4−3f

−6f+14=−4

Step 3: Subtract 14 from both sides.

−6f+14−14=−4−14

−6f=−18

Step 4: Divide both sides by -6.

−6f−6=−18−6f=3

Answer:

f=3

7 0
3 years ago
13. The radius of Earth is approximately 6.4 x 100 m. Use the formula V = 4/3pr^3
romanna [79]

<u>We are given</u>

  • Radius of Earth; 6.4 x 100 meters = 640 meters

Clearly, the shape of the earth is a sphere. Thus, to determine the volume of the earth, we will use a formula that determines the volume of a sphere.

\implies \text{Volume of sphere =} \   \dfrac{4\pi r^{3}}{3}

When we substitute the radius in the formula, we get;

\implies\text{Volume of sphere} = \dfrac{4\pi (640)^{3}}{3}

\implies\text{Volume of sphere} = \dfrac{4\pi (640)(640)(640)}{3}

Take π as 3.14

\implies\text{Volume of sphere} = \dfrac{4\pi (640)(640)(640)}{3}

\implies \text{Volume of sphere} = \dfrac{4(3.14)(640)(640)(640)}{3}

Simplify the numerator;

\implies \text{Volume of sphere} = \dfrac{4(3.14)(640)(640)(640)}{3}

\implies \text{Volume of sphere} = \dfrac{3292528640}{3}

Divide the numerator by 3;

\implies \text{Volume of sphere} = \dfrac{3292528640}{3}

\implies \text{Volume of sphere} = \boxed{1097509546.67 \ \text{m}^{3} } \ \ \ (\text{Estimated})

4 0
2 years ago
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