Answer: B
Step-by-step explanation:
Answer:
{5π/6, 11π/6}
Step-by-step explanation:
Since you have memorized the trig values of common angles, you know tan(π/6) = 1/√3, so cot(π/6) = √3.
The solution to this equation is ...
cot(θ) = -√3
so θ = -π/6 or, in the domain of interest, 11π/6. There is a corresponding quadrant II angle, 5π/6.
Answer:
The one on the bottom right
Step-by-step explanation:
Answer:
<h2><u><em>
a²+2ab+b²-c²</em></u></h2>
Step-by-step explanation:
Solve:
(a+b+c) (a+b-c)=
(a²+ab-ac+ab+b²-bc+ac+bc-c²)=
a²+ab-ac+ab+b²-bc+ac+bc-c²=
a²+2ab+0ac+b²+0bc-c²=
a²+2ab+b²-c²
Answer:
∡ZA = 66°
Step-by-step explanation:
Suplementary angles sum 180°
ZA + ZB = 180°
then:
(2x - 14)° + (3x-6)° = 180°
2x + 3x - 14 - 6 = 180
5x - 20 = 180
5x = 180 + 20
5x = 200
x = 200/5
x = 40
then:
∡ZA = (2x - 14)
∡ZA = (2*40 - 14)
∡ZA = (80-14)
∡ZA = 66°