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NemiM [27]
3 years ago
8

PLEASE IVE POSTED THIS FOUR TIMES CAN SOMEONE PLEASE HELP ME WRITE AN EQUATION FOR THIS! I GIVE BRAINLIST!

Mathematics
2 answers:
Leni [432]3 years ago
6 0
Y = -2/3x - 3. -2/3 is the slope and -3 is the y intercept.
borishaifa [10]3 years ago
5 0

Answer:

y= -2/3x-3

Step-by-step explanation:

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Solve the proportion<br> 16/50 = x/156.25
yuradex [85]
The answer for this proportion is 50.
156.25 times 16 =2,500
2,500 divided by 50=50
X=50
4 0
3 years ago
Read 2 more answers
Find the distance between the two numbers on a number line. Write your answer as a decimal.
dangina [55]

Answer:

-0.574

Step-by-step explanation:

Subtract the two numbers to get the solution

7 0
3 years ago
Will give brainliest answer!
kifflom [539]
5x + 60y = 35

x +y = 1.5 : rewrite as x = 1.5-y   and substitute this formula for x in the first one:

5(1.5-y) + 60y = 35

distribute:

7.5 - 5y + 60y = 35

combine like terms:

7.5 + 55y = 35

subtract 7.5 from both sides:

55y = 27.5

divide both sides by 55 to solve for  y

y = 27.5 / 55 = 0.5

now substiute 0.5 for y in the 2nd equation:

x + 0.5 = 1.5

x = 1.5 - 0.5 = 1

 he walked for 1 hour


8 0
3 years ago
What are the roots of this equation? x2-4x+9=0
zysi [14]

Considering the definition of zeros of a function, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

<h3>Zeros of a function</h3>

The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.

In summary, the roots or zeros of the quadratic function are those values ​​of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.

In a quadratic function that has the form:

f(x)= ax² + bx + c

the zeros or roots are calculated by:

x1,x2=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}

<h3>This case</h3>

The quadratic function is f(x) = x² + 4x +9

Being:

  • a= 1
  • b= 4
  • c= 9

the zeros or roots are calculated as:

x1=\frac{-4+\sqrt{4^{2}-4x1x9 } }{2x1}

x1=\frac{-4+\sqrt{16-36 } }{2x1}

x1=\frac{-4+\sqrt{-20 } }{2x1}

and

x2=\frac{-4-\sqrt{4^{2}-4x1x9 } }{2x1}

x2=\frac{-4-\sqrt{16-36 } }{2x1}

x2=\frac{-4-\sqrt{-20} }{2x1}

If the content of the root is negative, the root will have no solution within the set of real numbers. Then \sqrt{-20} has no solution.

Finally, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

Learn more about the zeros of a quadratic function:

brainly.com/question/842305

brainly.com/question/14477557

#SPJ1

6 0
1 year ago
Find the value of x.
Marta_Voda [28]
D i think because it’s talking about the angling
7 0
3 years ago
Read 2 more answers
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