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Dmitrij [34]
3 years ago
8

List the first 10 terms of each of these sequences.

Mathematics
2 answers:
harina [27]3 years ago
7 0
Q1)
the sequence should start with 10, after that each term is calculated by subtracting 3 from the previous term.
1st term - 10
2nd term - 10 - 3 = 7
3rd term  - 7 - 3 = 4
4th term - 4 - 3 = 1
5th term  - 1 - 3 = -2
6th term - -2 - 3 = -5
7th term - -5 - 3 = -8 
8th - -8 - 3 = -11
9th - -11 - 3  = -14
10th -14 - 3 = -17
the sequence is - 10,7,4,1,-2,-5,-8,-11,-14,-17

Q2) 
<span>the sequence whose nth term is the sum of the first n positive integers
In this we get the term by adding all the integers of the terms before that term 
1st term - n = 1 no terms before this , therefore 0 + n(1)  = 1
2nd term -n =2  sum of integers before - 1 + n( 2) = 3
3rd - 3+3 = 6
4th - 6+4 = 10 
5th - 10 + 5 = 15
6th - 15 + 6 = 21
7th  - 21 + 7 = 28
8th - 28 + 8 = 36
9th - 36 + 9 = 45
10th -  45 + 10 = 55
this is a triangular number pattern
this number pattern can be found out using ; n = (n x (n+1))/2

sequence is - 1,3,6,10,15,21,28,36,45,55

Q3)
</span>the sequence whose nth term is 3n − 2n
general term for this sequence is 3n − 2n
to find 1st term , n = 1
substituting n = 1 in the general term 
1st term - 3x1 - 2x1 = 3-2 = 1
2nd - 3x2- 2x2 = 6 - 4 = 2
3rd - 3x3 - 2x3 = 9-6 = 3
4th - 3x4 - 2x4 = 12 - 8 = 4
5th - 3x5 - 2x5 = 15 - 10 = 5
6th - 3x6 - 2x6 = 18 - 12 = 6
7th - 3x7 - 2x7 = 21 - 14 = 7
8th - 3 x8 - 2x8 = 24 - 16 = 8
9th - 3x9 - 2x9 = 27 - 18 = 9
10th - 3x10 - 2x10 = 30-20 = 10

sequence is 1,2,3,4,5,6,7,8,9,10

Q4)
<span>the sequence whose nth term is √ n
when n=1 1st term is </span>√1 = 1
1st term - √1 = 1
2nd term - √2 = 1.41
3rd - √3 = 1.73
4th - √4 = 2
5th - √5 = 2.23
6th- √6 = 2.44
7th - √7 = 2.65
8th- √8 = 2.82
9th - √9 = 3
10th - √10 = 3.16

The sequence is 1, 1.41, 1.73, 2, 2.23, 2.44, 2.65, 2.82, 3, 3.16

Q5)T<span>he sequence whose first two terms are 1 and 5 and each succeeding term is the sum of the two previous terms
</span>1st term - 1
2nd term - 5
3rd term - add 1st and 2nd term (1+5) = 6
4th term - add 2nd and 3rd terms (5+6) = 11
5th - add 3rd and 4th (6+11) = 17
6th - (11+17) = 28
7th - (17 + 28) = 45
8th - 45 + 28 = 73
9th - 73 + 45 = 118
10th - 73+ 118 = 191

sequence is - 1,5,6,11,17,28,45,73,118,191
Semenov [28]3 years ago
7 0
A. We start by writting down the general formula:
a(1) = 10
a(2) = a(1) - 3  
a(3) = a(2) - 3
a(n) = a(n-1) -3

Now we find first ten terms:
10, 7, 4 ,1, -2, -5, -8, -11, -14, -17

b. We start by writting down the general formula:
a(1) = 1
a(2) = 1 + 2
a(3) = 1 + 2 + 3
a(n) = 1 + 2 + ... + n

Now we find first ten terms:
1, 3, 6, 10, 15, 21, 28, 36, 45, 55

c. We start by writting down the general formula:
a(n) = 3n -2n = n

Now we find first ten terms:
1, 2, 3, 4, 5, 6, 7, 8, 9, 10

d. We start by writting down the general formula:
a(n)= \sqrt{n}

Now we find first ten terms:
1,  \sqrt{2},\sqrt{3}, 2,\sqrt{5},\sqrt{6},\sqrt{7},\sqrt{8},3,\sqrt{10}

e. We start by writting down the general formula:
a(1) = 1
a(2) = 5
a(3) = a(1) + a(2)
a(4) = a(2) + a(3)
a(n) = a(n-2) + a(n-1)

Now we find first ten terms:
1, 5, 6, 11, 17, 28, 45, 73, 118, 191
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Let's simplify step-by-step.

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Answer:

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Question 2 = d) 46.7 ft³

Step-by-step explanation:

Question 1

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The surface area of a square based pyramid(tent) =

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Where in the diagram,

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Question 2

For question 2, from the attached diagram, we can see that the diagram is a square based pyramid.

To calculate the amount of water that would fill the square based pyramid, we would have to find the Volume of the tent(square based pyramid).

The formula for the Volume of the tent(square based pyramid) = 1/3(a²h)

Where a = base edge

h = height of the pyramid.

From the diagram,

a = base edge => 4ft.

From the question,

h = height of the tent is given as how tall the tent is = 8.75ft.

Therefore, 1/3(a²h)

1/3 × (4ft)²× 8.75ft

= 46.67ft³

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(c) We have given expression \frac{\sqrt{3}-2i}{-2-\sqrt{3i}}

After rationalizing

\frac{\sqrt{3}-2i}{-2-\sqrt{3i}}\times \frac{-2+\sqrt{3i}}{-2+\sqrt{3i}}=\frac{-2\sqrt{3}+7i+2\sqrt{3}}{7}=\frac{7i}{7}=i

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