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3 years ago

Simplify 14 to the 15th power over 14 to the 5th power

Mathematics

1 answer:

stiks02 [169]3 years ago

6 0

Answer:

d) 14^10.

Step-by-step explanation:

14^15 / 14^5

= 14^(15-5(

= 14^10.

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Calculate the percent of increase for the $49 video game that is now being sold for $300.

prisoha [69]

Answer:

$\boxed{\color{blue}\textsf{The percentage increase in price is \textbf{512.22\% }}}$

Step-by-step explanation:

Here the earlier price of the video game was $ 49 and now it's being sold for $ 300 . We need to calculate the percentage increase in price .

So the increase in cost is $( 300 - 49 ) = $ 251 .

So we can calculate the % increase as ,

$\qquad\boxed{\boxed{\sf\% Increase = \dfrac{ Increase\ in \ price }{Original\ price } \times 100 }}$

Substituting the respective values :-

$\sf\implies \% Increase = \dfrac{ Increase\ in \ price }{Original\ price } \times 100 \\\\\sf\implies \% Increase =\dfrac{\$ 251}{\$ 49 }\times 100 \\\\\sf\implies \% Increase = 5.122 \times 100 \\\\\implies \boxed{\pink{\frak{ \% Increase = 512.24 \% }}}$

8 0

3 years ago

PLZ HELP!! PLZ !!!!!!!!!!!!!

adoni [48]

Answer:The volume of the reservoirs in in^3 is:

V = 30*14*(3/2)*12* (since 1 ft = 12 in)

1 gal = 231 in^3

((7/8)V) : 231 = ((7/8)30*14*(3/2)*12)/231 = 28.64 gal

28.64 gallons of oil are required to fill the reservoir to 7/8 of its depth.

Step-by-step explanation: i hope this help you if not please let me know :)

6 0

2 years ago

Read 2 more answers

1. Which of the following expressions are equivalent to? Select all that apply. A. 31 . 36 B. 31 . 35 C. 3-2 . 3-4 D. 32 . 3-8 E

Misha Larkins [42]

Answer: A and C

Step-by-step explanation:

3 0

3 years ago

1. Differentiate with respect to x:

natta225 [31]

9514 1404 393

Answer:

a) y' = x^2(3x·ln(6x) +1)

b) y' = 6e^(3x)/(1 -e^(3x))^2

Step-by-step explanation:

The applicable rules for derivatives include ...

d(u^n)/dx = n·u^(n-1)·du/dx

d(uv)/dx = (du/dx)v +u(dv/dx)

d(e^u)/dx = e^u·du/dx

d(ln(u))/dx = 1/u·du/dx

(a)

$y=x^3\ln{(6x)}\\\\y'=3x^2\ln{(6x)}+\dfrac{x^3\cdot6}{6x}\\\\\boxed{\dfrac{dy}{dx}=3x^3\ln{(6x)}+x^2}$

(b)

$y=\dfrac{1+e^{3x}}{1-e^{3x}}=1+\dfrac{2}{1-e^{3x}}=1+2(1-e^{3x})^{-1}\\\\y'=-2(1-e^{3x})^{-2} (-3e^{3x})\\\\\boxed{\dfrac{dy}{dx}=\dfrac{6e^{3x}}{(1-e^{3x})^2}}$

5 0

3 years ago

What is the probability that a random arrangement of the letters in the word SEVEN will have both 'E's next to each other?

BartSMP [9]

$|\Omega|=5!=120\\|A|=4\cdot2!\cdot3!=48\\\\P(A)=\dfrac{48}{120}=\dfrac{2}{5}=40\%$

5 0

2 years ago