3 years ago

PLS HELP ME FINISH THIS THANKS

Mathematics

1 answer:

Y_Kistochka [10]3 years ago

8 0

Pay attention to the even numbers

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What is the constant of variation,k, of the direct variation,y=kx,through (5,8)

grigory [225]

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form $\frac{y}{x}=k$ or $y=kx$

where

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the point $(5,8)$

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therefore

<u>the answer is</u>

$k=\frac{8}{5}$

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3 years ago

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Applying Properties of Exponents In Exercise,use the properties of exponents to simplify the expression.

vitfil [10]

Answer:

(A) $e^2$

(b) $e^{-3}$

(d) $e^3$

Step-by-step explanation:

We have given expression and we have to simplify the expression using exponent property

(A) $(\frac{1}{e})^{-2}$

So $(\frac{1}{e})^{-2}=\frac{1}{e^{-2}}=e^2$

(b) $(\frac{e^5}{e^2})^{-1}$

So $(\frac{e^5}{e^2})^{-1}=(e^{3})^{-1}=e^{-3}$

So $\frac{e^5}{e^3}=e^2$

(d) $\frac{1}{e^{-3}}=e^3$

7 0

2 years ago