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aliina [53]
2 years ago
9

10 x 10 +100 – 1000 = X

Mathematics
2 answers:
boyakko [2]2 years ago
4 0

Answer:-800

Step-by-step explanation: 10 times 10 is 100 plus another 100 is 200-1000 is -800 which is x

Readme [11.4K]2 years ago
4 0

Answer:

-800

Step-by-step explanation:

since you need to mutiply first,

10 x 10 +  100 - 1000 = X

100 + 100 - 1000 = X

200 - 1000 = X

-800 = X

hope it helps!!!

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The equations in this sytem were added to solve for x. What is the value of x?
svetoff [14.1K]

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I couldn't find an answer to this question lol<br> 2(x+6)=2(6+13x)
kherson [118]

Answer:

2(x+6) = 2(6+13x)

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7 0
3 years ago
Quadratic equations and complex numbers PLEASE HELPPPP ASAP
kondor19780726 [428]

we are given

27x^3-1=0

we can also write it as

(3x)^3-(1)^3=0

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a^3-b^3=(a-b)(a^2+ab+b^2)

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we get  

(3x)^3-(1)^3=(3x-1)((3x)^2+3x\times 1+(1)^2)

now, we can simplify it

27x^3-1=(3x-1)(9x^2+3x+1)

now, we can set it to 0

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and then we can solve for x

(3x-1)(9x^2+3x+1)=0

3x-1=0

x=\frac{1}{3}

9x^2+3x+1=0

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x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

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and we get

x=\frac{-3\pm \sqrt{3^2-4\cdot \:9\cdot \:1}}{2\cdot \:9}

x=-\frac{1}{6}+i\frac{\sqrt{3}}{6},\:x=-\frac{1}{6}-i\frac{\sqrt{3}}{6}

So, we will get solution as

x=\frac{1}{3},\:x=-\frac{1}{6}+i\frac{\sqrt{3}}{6},\:x=-\frac{1}{6}-i\frac{\sqrt{3}}{6}...............Answer

5 0
3 years ago
Select the statement which is true about the functions over the interval [1, 2].
givi [52]

Answer:

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Step-by-step explanation:

6 0
2 years ago
If K = {(x, y)|x - y = 5}, find the corresponding range of y for the domain {0, 2, 4}. {-5, -3, -1} {0, 2, 4} {5, 7, 9}
Aleks04 [339]

Answer:

The range = {-5 , -3 , -1} ⇒ first answer

Step-by-step explanation:

* In any equation the values of x are the domain of it and

 the values of y are the range of it

* So to find the range of any equation substitute the values

 of x (domain) in the equation to get the corresponding

  values of y (range)

* In the problem

∵ K = {(x , y): x - y = 5}

∵ The domain is {0 , 2 , 4}

* Lets find K(0) , K(2) , K(4)

∵ K(0) = (0) - y = 5

∴ -y = 5 ⇒ Multiply both sides by -1

∴ y = -5

∵ K(2) = (2) - y = 5

∴ 2 - y = 5 ⇒ subtract 2 from both sides

∴ -y = 3 ⇒ Multiply both sides by -1

∴ y = -3

∵ K(4) = (4) - y = 5

∴ 4 - y = 5 ⇒ subtract 4 from both sides

∴ -y = 1 ⇒ Multiply both sides by -1

∴ y = -1

* The range = {-5 , -3 , -1}

8 0
3 years ago
Read 2 more answers
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