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Fantom [35]
3 years ago
9

ALGEBRA 1, SEMESTER 2

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
8 0

So firstly, we have to find f(x) when x = 8 and x = 0. Plug the two numbers into the x variable of the function to solve for their f(x):

f(0)=\frac{2*0+3}{3*0-3}\\ f(0)=\frac{0+3}{0-3}\\ f(0)=\frac{3}{-3}\\ f(0)=-1\\ \\ f(8)=\frac{2*8+3}{3*8-3}\\ f(8)=\frac{16+3}{24-3}\\ f(8)=\frac{19}{21}

Now that we have their y's, we can use the slope, aka average rate of change, formula, which is \frac{y_2-y_1}{x_2-x_1} . Using what we have, we can solve it as such:

\frac{\frac{19}{21}-(-1)}{8-0}=\frac{\frac{40}{21}}{8}=\frac{40}{21*8}=\frac{40}{168}=\frac{5}{21}

In short, the average rate of change from x = 0 to x = 8 is 5/21.

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Tresset [83]

Answer:

17

Step-by-step explanation:

Given

b(1)=16\\ \\b(n)=b(n-1)+1

Finding the second term of the sequence means to find b(2). To find b(2) substitute n=2 into the second expression:

b(2)=b(2-1)+1\\ \\b(2)=b(1)+1\\ \\b(2)=16+1\\ \\b(2)=17

6 0
3 years ago
Please help 15 points<br> x2≥−4
Nutka1998 [239]

Answer:

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Step-by-step explanation:

6 0
3 years ago
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Zepler [3.9K]

When you write the equation of a circle in the form

(x-x_0)^2+(y-y_0)^2=r^2

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7 0
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Roughly estimate the volume of a tennis ball in cubic cm by using 6 cm for diameter and 3 for pi. round the answer to the neares
galben [10]

The volume of ball is 113.04 cubic centimeter

<em><u>Solution:</u></em>

Given that we have to find the volume of tennis ball

Since the ball is of sphere shape, we can use the sphere formula

<em><u>The volume of sphere is given by formula:</u></em>

V = \frac{4}{3} \times \pi \times r^3

Where, "V" is the volume and "r" is the radius

Given that,

Diameter = 6 cm

Therefore,

Radius = \frac{diameter}{2}\\\\Radius = \frac{6}{2}=3

<em><u>Substituting in formula, we get</u></em>

V = \frac{4}{3} \times 3.14 \times 3^3\\\\V = 4 \times 3.14 \times 3^2\\\\V = 12.56 \times 9\\\\V = 113.04

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3 0
3 years ago
7+8 is equal to what?
AURORKA [14]

Answer:

15

Step-by-step explanation:

8 0
3 years ago
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