ALGEBRA 1, SEMESTER 2

1 answer:

8 0

So firstly, we have to find f(x) when x = 8 and x = 0. Plug the two numbers into the x variable of the function to solve for their f(x):

$f(0)=\frac{2*0+3}{3*0-3}\\ f(0)=\frac{0+3}{0-3}\\ f(0)=\frac{3}{-3}\\ f(0)=-1\\ \\ f(8)=\frac{2*8+3}{3*8-3}\\ f(8)=\frac{16+3}{24-3}\\ f(8)=\frac{19}{21}$

Now that we have their y's, we can use the slope, aka average rate of change, formula, which is $\frac{y_2-y_1}{x_2-x_1}$ . Using what we have, we can solve it as such:

$\frac{\frac{19}{21}-(-1)}{8-0}=\frac{\frac{40}{21}}{8}=\frac{40}{21*8}=\frac{40}{168}=\frac{5}{21}$

In short, the average rate of change from x = 0 to x = 8 is 5/21.

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Good luck !

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