All categories

3 years ago

What is the easiest method to solve this equation?

Mathematics

2 answers:

Gennadij [26K]3 years ago

4 0

Using the quadratic equation would be the easiest

Kryger [21]3 years ago

4 0

Answer: C (Quadratic Formula)

Explanation:

No reason really. No way to factor by using “nice” numbers. Isolating the variable (e.g. completing the square) gives us “complicated” fractions. It therefore can’t be D. The answer is C

You might be interested in

DIC A student has a total of $3000 in student loans that will be paid with a 48-month installment loan with monthly payments of

gtnhenbr [62]

Answer:

The APR of the loan was 18.30%.

Step-by-step explanation:

Given that a student has a total of $ 3000 in student loans that will be paid with a 48-month installment loan with monthly payments of $ 73.94, to determine the APR of the loan to the nearest one-half of a percent the following calculation must be done:

3,000 = 100

(73.94 x 48) = X

3,000 = 100

3,549.12 = X

3,549.12 x 100 / 3,000 = X

354,912 / 3000 = X

118.30 = X

118.30 - 100 = 18.30

Therefore, the APR of the loan was 18.30%.

5 0

2 years ago

Find the square roots of the two factors of √36 and multiply them.

PolarNik [594]

Answer:

The square root is 6.

Step-by-step explanation:

4 0

3 years ago

During the 7th examination of the Offspring cohort in the Framingham Heart Study, there were 1219 participants being treated for

AlexFokin [52]

Answer:

95% confidence interval for the proportion of the population which are on treatment is [0.3293 , 0.3607].

Step-by-step explanation:

We are given that during the 7th examination of the Offspring cohort in the Framing ham Heart Study, there were 1219 participants being treated for hypertension and 2,313 who were not on treatment.

The sample proportion is : $\hat p$ = x/n = 1219/3532 = 0.345

Firstly, the pivotal quantity for 95% confidence interval for the proportion of the population is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion = 0.345

n = sample of participants = 3532

p = population proportion

Here for constructing 95% confidence interval we have used One-sample z proportion statistics.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level of

significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

95% confidence interval for p= [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.345-1.96 \times {\sqrt{\frac{0.345(1-0.345)}{3532} } }$ , $0.345+1.96 \times {\sqrt{\frac{0.345(1-0.345)}{3532} } }$ ]