First you substitute 18 into c and solve what's inside the paranthesis which is 56. Distribute the 2 to 56 and you should be getting 112 as your answer. 2x(74-c)=112 if c=18.
Answer: Casey should buy 48 square yards of carpet
Step-by-step explanation: If Casey's room has two sections, which are a square section and a rectangular section, we shall calculate the total area of each section separately to start with. The square section has sides measuring 4 yards each, then the area of that section can be calculated as;
Area = 4 x 4 (all sides of a square are equal in length)
Area = 16 square yards.
Also the rectangular section has the same width as the square section, that is, 4 yards. The rectangular section has twice the length of the square section, that is, twice of 4 yards which is 8 yards. Hence the area of the rectangular section is calculated as;
Area = 4 x 8
Area = 32 square yards
Therefore, the total measurement of carpet in square yards for her room shall be area of both sections added together.
Total area = 16 square yards + 32 square yards
Total area = 48 square yards
Answer:
About 90% of visitors at the Yellowstone National Park was changed from 2000 to 2001.
Step-by-step explanation:
Answer:
Undeterminable to me
Step-by-step explanation:
Justin:180cm - 8cm per minute
Taylor:160cm + 6cm per minute
Doing the math, I could not determine the answer. So if there is an answer for "Never" or "No" I think it would be the answer
Answer:
![Area = 41.714](https://tex.z-dn.net/?f=Area%20%3D%2041.714)
![m^2](https://tex.z-dn.net/?f=m%5E2)
Step-by-step explanation:
Given
Rectangle:
![Length = 2.5m](https://tex.z-dn.net/?f=Length%20%3D%202.5m)
![Width = 6m](https://tex.z-dn.net/?f=Width%20%3D%206m)
Semicircle
![Diameter = 6m](https://tex.z-dn.net/?f=Diameter%20%3D%206m)
Quarter circle
![Radius = 4m](https://tex.z-dn.net/?f=Radius%20%3D%204m)
Required
The square meters of sod will Carter remove [Missing information]
To do this, we simply calculate the area of each flower beds.
For the rectangle:
![A_1= Length * Width](https://tex.z-dn.net/?f=A_1%3D%20Length%20%2A%20Width)
![A_1= 2.5m * 6m](https://tex.z-dn.net/?f=A_1%3D%202.5m%20%2A%206m)
![A_1= 15m^2](https://tex.z-dn.net/?f=A_1%3D%2015m%5E2)
For the semicircle
![A_2 = \frac{1}{2}\pi r^2](https://tex.z-dn.net/?f=A_2%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Cpi%20r%5E2)
Where
![r=\frac{6}{2} = 3](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B6%7D%7B2%7D%20%3D%203)
So:
![A_2 = \frac{1}{2} *\frac{22}{7} * 3^2](https://tex.z-dn.net/?f=A_2%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2A%5Cfrac%7B22%7D%7B7%7D%20%2A%203%5E2)
![A_2 = \frac{1}{2} *\frac{22}{7} * 9](https://tex.z-dn.net/?f=A_2%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2A%5Cfrac%7B22%7D%7B7%7D%20%2A%209)
![A_2 = \frac{1*22*9}{2*7}](https://tex.z-dn.net/?f=A_2%20%3D%20%5Cfrac%7B1%2A22%2A9%7D%7B2%2A7%7D)
![A_2 = \frac{198}{14}](https://tex.z-dn.net/?f=A_2%20%3D%20%5Cfrac%7B198%7D%7B14%7D)
![A_2 = 14.143](https://tex.z-dn.net/?f=A_2%20%3D%2014.143)
For the quarter circle
![A_3 = \frac{1}{4}\pi r^2](https://tex.z-dn.net/?f=A_3%20%3D%20%5Cfrac%7B1%7D%7B4%7D%5Cpi%20r%5E2)
![A_3 = \frac{1}{4} * \frac{22}{7} * 4^2](https://tex.z-dn.net/?f=A_3%20%3D%20%5Cfrac%7B1%7D%7B4%7D%20%2A%20%5Cfrac%7B22%7D%7B7%7D%20%2A%204%5E2)
![A_3 = \frac{22}{7} * 4](https://tex.z-dn.net/?f=A_3%20%3D%20%5Cfrac%7B22%7D%7B7%7D%20%2A%204)
![A_3 = \frac{88}{7}](https://tex.z-dn.net/?f=A_3%20%3D%20%5Cfrac%7B88%7D%7B7%7D)
![A_3 = 12.571](https://tex.z-dn.net/?f=A_3%20%3D%2012.571)
Total area is:
![Area = A_1 + A_2 + A_3](https://tex.z-dn.net/?f=Area%20%3D%20A_1%20%2B%20A_2%20%2B%20A_3)
![Area = 15 + 14.143 + 12.571](https://tex.z-dn.net/?f=Area%20%3D%2015%20%2B%2014.143%20%2B%2012.571)
![Area = 41.714](https://tex.z-dn.net/?f=Area%20%3D%2041.714)
![m^2](https://tex.z-dn.net/?f=m%5E2)