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3 years ago

Please help extra points and Mark brainless

Mathematics

2 answers:

vovikov84 [41]3 years ago

8 0

Answer:

Top choice: x coordinate --> negative, y coordinator ---> negative

Step-by-step explanation:

Reflection over y axis : (x,y) ---> (-x,y)

Dimas [21]3 years ago

4 0

Answer:

Step-by-step explanation:

If the point is in the positive x coordinate and negative y coordinate. Therefore, the coordinate or point will be the same as well.

X grid is positive and y grid is negative.

The point will be the same information too.

I hope this helped. If this is correct please say so in the comments below. I don't want this to affect anybody else. Any questions? Ask in the comments below as well.

Signed,

tyreefranklinjr

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The railroad company wants to sell $3,854 in tickets. If each ticket costs $41, how many tickets will the railroad have to sell

nikdorinn [45]

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The railroad company have to sell 94 tickets to meet its goal.

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3 years ago

israel started to solve a radical equation in this way: square root of x plus 6 − 4 = x square root of x plus 6 − 4 4 = x 4 squa

agasfer [191]

Lets solve our radical equation $\sqrt{x+6}-4=x$ step by step.

Step 1 add 4 to both sides of the equation:

$\sqrt{x+6} -4+4=x +4$

$\sqrt{x} +6=x+4$

Step 2 square both sides of the equation:

$\sqrt{x+6} =x+4$

$\sqrt{x+6}^2 =(x+4)^2$

$x+6=(x+4)^2$

Step 3 expand the binomial in the right hand side:

$x+6=x^2+8x+16$

Step 4 simplify the expression:

$0=x^2+8x-x+16-6$

$x^2+7x+10=0$

Step 5 factor the expression:

$(x+2)(x+5)=0$

Step 6 solve for each factor:

$x+2=0$ or $x+5=0$

$x=-2$ or $x=-5$

Now we are going to check both solutions in the original equation to prove if they are valid:

For $x=-2$

$\sqrt{x+6}-4=x$

$\sqrt{-2+6}-4=-2$

$\sqrt{4}-4=-2$

$2-4=-2$

$-2=-2$

The solution $x=2$ is a valid solution of the rational equation $\sqrt{x+6}-4=x$ .

For $x=-5$

$\sqrt{x+6}-4=x$

$\sqrt{-5+6}-4=-5$

$\sqrt{1}-4=-5$

$1-4=-5$

$-3\neq -5$

Since -3 is not equal to -5, the solution $x=-5$ is not a valid solution of the rational equation $\sqrt{x+6}-4=x$ ; therefore, $x=-5$ is an extraneous solution of the equation.

We can conclude that even all the algebraic procedures of Israel are correct, he did not check for extraneous solutions.

An extraneous solution of an equation is the solution that emerges from the algebraic process of solving the equation but is not a valid solution of the equation. Is worth pointing out that extraneous solutions are particularly frequent in rational equation.

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4 years ago

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Nadya [2.5K]

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Mumz [18]

Answer:

Step-by-step explanation:

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