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pantera1 [17]
2 years ago
10

I don't know how to do this!!​

Mathematics
1 answer:
saw5 [17]2 years ago
6 0
3x-1=77 (due to exterior alternate angle)
Or, 3x=77-1
or, 3x=76
or, x=76/3
or, x=25.3
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The ball will hit the ground at 2 seconds.

Step-by-step explanation:

Given that,

The path of the ball = h(x)=−2x2+1x+6

Here,

x is the time while h is the height of ball.

When the ball will hit the ground, the height will become zero. Therefore,

h(x)=−2x2+1x+6

0 =−2x2+1x+6

or

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This is a quadratic equation, hence by applying quadratic equation formula:

x = \frac{-b +- \sqrt{b^{2} - 4ac }   }{2a}

here,

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x = \frac{-(-1) +- \sqrt{-1^{2} - 4.2.-6 }   }{2.2}

x = \frac{1 +- \sqrt{1 + 48 }   }{4}

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x = \frac{1 +- 7   }{4}

x = 2, -3/2

As the time cannot be negative. Therefore, the ball will hit the ground at 2 seconds.

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