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avanturin [10]
3 years ago
5

Due tomorrow i need help​

Mathematics
1 answer:
Airida [17]3 years ago
7 0

Answer:

13x is your answer

Step-by-step explanation:

just add 6x + 7

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A musician plans to perform 4 selections. In how many ways can she arrange the musical selections?
kari74 [83]

Answer:

The answer is 24 in my opinion

Step-by-step explanation:

1)1 2 3 4

2)1 2 4 3

3)1 3 2 4

4)1 3 4 2

5)1 4 3 2

6)1 4 2 3

  • Just multiply the 4 with 6 then you get the answer. Hope this is correct.
4 0
3 years ago
Read 2 more answers
Sally has two pieces of fabric that are 128 inches long. She needs to cut each piece of fabric into multiple pieces that are 6 i
Alborosie
42 pieces. Add 128+128=256, then divide that by 6 which is 42.6, and you have 42 pieces (complete pieces, but if it doesn’t ask for complete pieces then your answer is 42.6)
3 0
3 years ago
A Geiger counter counts the number of alpha particles from radioactive material. Over a long period of time, an average of 14 pa
UkoKoshka [18]

Answer:

0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Over a long period of time, an average of 14 particles per minute occurs. Assume the arrival of particles at the counter follows a Poisson distribution. Find the probability that at least one particle arrives in a particular one second period.

Each minute has 60 seconds, so \mu = \frac{14}{60} = 0.2333

Either no particle arrives, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-0.2333}*(0.2333)^{0}}{(0)!} = 0.7919

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.7919 = 0.2081

0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.

8 0
4 years ago
And these. I’m desperate help
denis23 [38]
7 is A and 8 is also A
3 0
3 years ago
Simplify -5(2x-7)-4x+5
ivanzaharov [21]

Answer:

-14x+35

Step-by-step explanation:

-10x+35-4x+5

-14x+40

7 0
3 years ago
Read 2 more answers
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