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Alexandra [31]
3 years ago
9

Ill give you brainliest pleaseeeeeeee help me

Mathematics
1 answer:
ruslelena [56]3 years ago
4 0
Line D and C because they are not parallel but distorted or unsymmetrical
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3^-1 ___ 1/4<br><br> =<br> &lt;<br> &gt;<br> answer thanks
dybincka [34]

3⁻¹  is <u>greater than </u>1/4

<u>Step-by-step explanation:</u>

3⁻¹ is nothing but the inverse of 3 .

So it can be written as 1/3.

Value of 1/3 can be found by dividing 1 by 3 to be 0.333...

Value of 1/4 can be found by dividing 1 by 4 to be 0.25

So 0.333 > 0.25

1/3 > 1/4

∴ 3⁻¹ > 1/4

6 0
3 years ago
Hi i need help asap plzzzzzzz
uysha [10]

Answer:?

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
(3 − 13x − 7x2) − (5x2 + 12x − 10)
Brums [2.3K]
113 is the answer hope i help u
5 0
3 years ago
Read 2 more answers
Colin has a pad with x pieces of paper on it. For his first class, he wrote on 5 fewer than half of the pieces of paper in the p
PIT_PIT [208]

Answer:

Colin has <em>8 sheets </em>left for his third class.

Step-by-step explanation:

Given that:

Total Number of pieces of papers = x

Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad

Writing the equation:

\text{Number of pieces of papers used for 1st class =} \dfrac{x}{2} -5 ...... (1)

Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.

\text{Number of pieces of papers used for 2nd class =} \dfrac{x}{2} -5+2 = \dfrac{x}2 -3 ...... (2)

Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class

\text{number of pieces of papers left for the third class = }x-(\dfrac{x}{2}-5)-(\dfrac{x}{2}-3)\\\Rightarrow x-\dfrac{x}2-\dfrac{x}2+5+3\\\Rightarrow x-x+5+3\\\Rightarrow 8

So, the answer is:

Colin has <em>8</em> <em>sheets </em>left for his third class.

5 0
3 years ago
Solve for m. -19m − 19 = 4m − 4m + 19
dangina [55]
-19m-19 = 4m-4m+19
-19m-19 = 0+19
-19m = 19+19
-19m = 38
m = 38÷(-19)
m = -2
7 0
3 years ago
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