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3 years ago

Line p had a slope of 5/4. line q is perpendicular to line p. what is the slope of line q?

Mathematics

1 answer:

coldgirl [10]3 years ago

6 0

Answer: -4/5

Step-by-step explanation: It's important to understand

that perpendicular lines have negative reciprocal slopes.

"Negative reciprocal" is just a fancy way

of saying flip the fraction and change the sign.

So if we flip the fraction 5/4 we get 4/5 and

if we change the sign we get -4/5.

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Please answer ASAP! An explanation is a MUST REQUIREMENT in order to receive points and the Brainliest answer. Thank you.

alexdok [17]

Group and factor/undistribute

(x^2y^3-2y^3)+(-2x^2+4)
(y^3)(x^2-2)+(-2)(x^2-2)
see the (x^2-2) is common term so undistribute
(x^2-2)(y^2-2)

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4 0

3 years ago

Find the volume of the cone shown as a decimal rounded to the tenth. 22m 12m

Luda [366]

Answer:

Step-by-step explanation:

the volume (V) of a cone is calculated as

V = $\frac{1}{3}$ πr²h ( r is the radius , h is the height )

here diameter = 12 , so r = 12 ÷ 2 = 6 and h = 22 , then

V = $\frac{1}{3}$ π × 6² × 22

= $\frac{1}{3}$ π × 36 × 22

= $\frac{1}{3}$ π × 792 ( cancel 3 and 792 by 3 )

= π × 264

≈ 829.4 m³ ( to the nearest tenth )

3 0

2 years ago

Rewrite the expression in the form 9^n<br> (9^3) (9^12)

BartSMP [9]

Answer:

${9}^{15}$

Step-by-step explanation:

$( {9}^{3} ) \times ( {9}^{12} ) = 9 {}^{3 + 12} = {9}^{15} \\$

5 0

3 years ago

CAN SOMEONE PLEASE HELP ME ASAP PLEASEEEE!!!

Rom4ik [11]

Answer:

11.4

Step-by-step explanation:

So we know that Triangle ACB is similar to Triangle EFD.

This means that their sides are proportional to each other.

We want to find x or side AB. To do so, we can set up a proportion.

The proportional side to AB is ED. Let's also use BC since we know its value. The proportional side to BC is DF. Thus:

$\frac{AB}{ED}=\frac{BC}{DF}$

Substitute x for AB, 3.8 for Ed, 15 for BC, and 5 for DF. Thus:

$\frac{x}{3.8}=\frac{15}{5}$

Reduce the right:

$\frac{x}{3.8}=\frac{3}{1}$

Cross multiply:

$x=11.4$

So, the value of x is 11.4

And we're done!

7 0

3 years ago

Forces of 9 lbs and 13 lbs act at a 38º angle to each other. Find the magnitude of the resultant force and the angle that the re

fiasKO [112]

Answer: $R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}$

Step-by-step explanation:

Given

Two forces of 9 and 13 lbs acts $38^{\circ}$ angle to each other

The resultant of the two forces is given by

$\Rightarrow R=\sqrt{a^2+b^2+2ab\cos \theta}$

Insert the values

$\Rightarrow R=\sqrt{9^2+13^2+2(9)(13)\cos 38^{\circ}}\\\Rightarrow R=\sqrt{81+169+184.394}\\\Rightarrow R=\sqrt{434.394}\\\Rightarrow R=20.84\ lb$

Resultant makes an angle of

$\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}$

So, the resultant makes an angle of $22.57^{\circ}$ with 9 lb force

Angle made with 13 lb force is $38^{\circ}-22.57^{\circ}=15.43^{\circ}$

7 0

3 years ago

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