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vivado [14]
3 years ago
6

(3,-3), slope 3 write an equation of the line that passes through the given point and has the given slope

Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
8 0

Answer:

y=3(x+3)+3

Step-by-step explanation:

I think this is correct

tester [92]3 years ago
4 0

Answer:

y = 3x - 12

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 3, thus

y = 3x + c ← is the partial equation

To find c substitute (3, - 3) into the partial equation

- 3 = 9 + c ⇒ c = - 3 - 9 = - 12

y = 3x - 12 ← equation of line

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Elis [28]
I think it’s A because they only intersect once.
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3 years ago
In triangle ABC, the measure of angle B is 50 degrees. Select all possible values for the measures of A and C if ABC is an acute
galben [10]

Answer:

Step-by-step explanation:

Sum of angle in a triangle = 180°

<A+<B+<C = 180

Given <B = 50°

Substituting into the formula

<A+50+<C = 180

<A+<C = 180-50

<A+<C = 130°

Since the ∆ABC is an acute triangle, the angles <A and <C must be angles less than 90° since acute angles are angles less than 90°

The possible values of <A and <C that will be acute and give a sum of 130° are;

∠A= 58° and ∠C= 72°

∠A= 80° and ∠C= 50°

∠A= 60° and ∠C= 70°

You can see that all the Angles are less than 90° and their sum is 130°

5 0
3 years ago
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Maru [420]

Answer:

289

Step-by-step explanation:

Raise 17 to the power of 2

Is this what you are asking for

3 0
2 years ago
Read 2 more answers
Factor completely. x 3 + 6x 2 - 4x - 24
Ulleksa [173]
You can factor (x^3 and 6x^2) and (-4x and -24).

So x^2(x+6) - 4(x+6)

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5 0
3 years ago
Geometric Series assistance
Levart [38]

we have been asked to find the sum of the series

\sum _{n=1}^5\left(\frac{1}{3}\right)^{n-1}

As we know that a geometric series has a constant ratio "r" and it is defined as

r=\frac{a_{n+1}}{a_n}=\frac{\left(\frac{1}{3}\right)^{\left(n+1\right)-1}}{\left(\frac{1}{3}\right)^{n-1}}=\frac{1}{3}

The first term of the series is a_1=\left(\frac{1}{3}\right)^{1-1}=1

Geometric series sum formula is

S_n=a_1\frac{1-r^n}{1-r}

Plugin the values we get

S_5=1\cdot \frac{1-\left(\frac{1}{3}\right)^5}{1-\frac{1}{3}}

On simplification we get

S_5=\frac{121}{81}

Hence the sum of the given series is \frac{121}{81}

5 0
3 years ago
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