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3 years ago

Mathhhhhhhhhhhhhhhhhh

Mathematics

1 answer:

Vlada [557]3 years ago

8 0

Answer:

<DBE and < EBC are linear pair.

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Kristen can run at 9kmh-1 and walk at 3kmh-1. She completed a 42km marathon in 6 hours. What distance did Kristen run during the

Hatshy [7]

Kristen completed 42 km. We will imagine that she ran all 6 hours. => 9 * 6 =54 km which is more than she actually completed. So we will find a 9 Multiple less than 42 km and that will be 36 km. (9 * 4 = 36 km completed by running) and the rest until 42 were completed by walking (3 * 2 = 6; 6 + 36 =42).

6 0

3 years ago

PLEASE HELP I WILL GIVE BRAINLIEST

SOVA2 [1]

Answer:

65 degrees

Step-by-step explanation:

The angles will sum up to 360, just do 360 - all known angles

360 - 90 - 128 - 77 = 65

3 0

3 years ago

Read 2 more answers

Please help i am very confused

Step2247 [10]

Answer:

$\sqrt{80}$

80 is the number in the square root

Step-by-step explanation:

$d = \sqrt{(x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2} } \\d = \sqrt{(4-(-4) )^{2} +(5- 1 )^{2} }\\d = \sqrt{(4+4 )^{2} +4^{2}\\d = \sqrt{8^{2} +4^{2} }\\d=\sqrt{64 +16}\\d=\sqrt{80}$

4 0

3 years ago

PLEASE ANSWER ITS THE LAST QUESTION!!

Vika [28.1K]

Answer:

The length of BC would be 12.2 mm.

Step-by-step explanation:

Given,

In triangle ABC,

∠BAC = 90°,

Thus by the Pythagoras theorem,

We have,

AB = 9.6 mm and CA = 7.6 mm,

By substituting the values,

Step-by-step explanation:

8 0

2 years ago

A coffee shop covers it coffee cups for holiday seasons. Their cups are cylindrical, have a 2 inch radius, and a height of 6 inc

slega [8]

Answer:

Surface area of square box cover is 4x12=48 $in^{2}$

Step-by-step explanation:

Given cylindrical cup have 2 in of radius and height of 6 in.

It is said that we need to cover the cup leaving top and bottom of cup.

To find how much material to cover:

After covering the cup, square box will be formed around the cup.

As shown in figure, Top view of square cup and box.

One face of box has length of diameter of cup = 2 in and height of box as height of cup = 6 in

Therefore, Area of one face of square box is length x height = 2 x 6 =12 $in^{2}$

Since, Box having 4 faces

Surface area of square box cover = 4 x area of one face of box

= 4x12=48 $in^{2}$

8 0

3 years ago