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makvit [3.9K]
3 years ago
10

How this is so hard plz help me on this

Mathematics
1 answer:
omeli [17]3 years ago
3 0
5) EJ
6) EJF
7) BJA
8) JB
9) obtuse angle
10) right angle
11) AFB & BFC
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What are two numbers that add to make 36 with one of the numbers be exactly twice the other
Tema [17]
To solve, set an equation:
First Number: x
Second Number: 2x

x+2x=36
3x=36
divide both sides by 3
x=13

First Number: (x) 12
Second Number: (2x) 24

Answers: 12 and 24
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3 years ago
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The quotient of a number and 3 is 6
KengaRu [80]

Step-by-step explanation:

the quotient of a number and 3 is 6

Solution,

Let the number be x, then

\frac{x}{3}  = 6 \\ x = 6 \times 3 \\ x = 18

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2 years ago
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The price of a dress is reduced by 50​%.when the dress still does not​ sell, it is reduced by 50​% of the reduced price. if the
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Suppose that a box contains one fair coin (Heads and Tails are equally likely) and one coin with Heads on each side. Suppose fur
stealth61 [152]

Using conditional probability, it is found that there is a 0.1 = 10% probability that the chosen coin was the fair coin.

Conditional Probability

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem:

  • Event A: Three heads.
  • Event B: Fair coin.

The probability associated with 3 heads are:

  • 0.5^3 = 0.125 out of 0.5(fair coin).
  • 1 out of 0.5(biased).

Hence:

P(A) = 0.125 + 0.5 = 0.625

The probability of 3 heads and the fair coin is:

P(A \cap B) = 0.5(0.125) = 0.0625

Then, the conditional probability is:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0625}{0.625} = 0.1

0.1 = 10% probability that the chosen coin was the fair coin.

A similar problem is given at brainly.com/question/14398287

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3 years ago
Suppose you drive from here to there at a speed of 30mph and then drive 60mph. What is your average speed?
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Looooooooooooooooooooooooooooooooooool
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