So before we can decide which graph it is, we have to find the zeros (x-intercepts) of this graph. We can do this by setting y to 0.
Firstly, factor out 3x on the right side of the equation: 
Next, use the zero product property to solve y = 0:
So we know that the zeros of this equation are (4,0) and (0,0). Looking at the four graphs, the only graph that has a line crossing those 2 points is the first graph. Therefore, the graph of this equation is the first graph.
Answer: natural numbers
Step-by-step explanation:
Let P(x,y) be a point on the parabola. The definition of a parabola is the squared distance from P to focus F(2,2) equals the squared distance to the directrix x=8.
squared distance from P(x,y) to focus F(2,2)
(x - 2)² + (y - 2)²
squared distance from P(x,y) to the directrix x=8.
(x-8)²
Those are equal in a parabola,
(x - 2)² + (y - 2)² = (x-8)²
x² - 4x + 4 + y² - 4y + 4 = x² - 16x + 64
y² - 4y - 46 = -12x
That's a sideways parabola,
x = -(y² - 4y - 46)/12
The distance between -0.15 and 0.7 would be 22
Because you add .15 and .7 because that's how many places you had to move on a number line
