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Sati [7]
4 years ago
8

Find the center, vertices, and foci of the ellipse with equation 2x2 + 9y2 = 18.

Mathematics
1 answer:
vovangra [49]4 years ago
7 0
We have that
2x² + 9y²<span> = 18------> divided by 18
so
</span>2x² /18+ 9y²/18 = 18/18------> x/9² + y²/2 = 1

Part a)
the equation of the ellipse if of the form
(x-h)²/a²+(y-k)²/b²=1
where (h,k) is the center
in this problem
(h,k) is (0,0) ------> is the origin
a²=9------> a=3
b²=2-----> b=√2

Part b)
vertices are
(h+a,k)  and (h-a,k)
(0+3,0)-----> (3,0)
(0-3,0)----> (-3,0)

Part c)
foci are
(h+c.k)  and (h-c, k)
where 
c²=a²-b²-----> c²=9-2-----> c²=7-----> c=√7

the foci are
(0+√7, 0)-----> (√7,0)
(0-√7,0)------> (-√7,0)


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A financial talk show host claims to have a 55.3 % success rate in his investment recommendations. You collect some data over th
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There is a 25.52% probability of observating 4 our fewer succesful recommendations.

Step-by-step explanation:

For each recommendation, there are only two possible outcomes. Either it was a success, or it was a failure. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

p = 0.553, n = 10

If the claim is correct and the performance of recommendations is independent, what is the probability that you would have observed 4 or fewer successful:

This is

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.553)^{0}.(0.447)^{10} = 0.0003

P(X = 1) = C_{10,1}.(0.553)^{1}.(0.447)^{9} = 0.0039

P(X = 2) = C_{10,2}.(0.553)^{2}.(0.447)^{8} = 0.0219

P(X = 3) = C_{10,3}.(0.553)^{3}.(0.447)^{7} = 0.0724

P(X = 4) = C_{10,4}.(0.553)^{4}.(0.447)^{6} = 0.1567

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0003 + 0.0039 + 0.0219 + 0.0724 + 0.1567 = 0.2552

There is a 25.52% probability of observating 4 our fewer succesful recommendations.

3 0
3 years ago
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