Answer:
<u>AP = 13</u>
Step-by-step explanation:
See the attached figure.
CD = 10 and XY = 24
Line XY bisects and is perpendicular to AB and CD
∴ XY bisects at Y
∴ CY = 0.5 CD = 0.5 * 10 = 5
And from the geometry of the shape
P is the midpoint of XY
∴ XP = YP = 0.5 XY = 0.5 * 24 = 12
XY is perpendicular to CD
∴ ΔPYC is a right triangle at Y
∴ PC (hypotenuse) =
From the figure AP = PC = 13
Answer:
It can be proved that the circle R is similar to the circle Q by translating the circle R a displacement of (-6, 12).
Step-by-step explanation:
We can demonstrate that Circle R is similar to Circle Q by translating the center of the former one to the center of latter one. Meaning that every point of circle R experiments the same translation. Vectorially speaking, a translation is defined by:
(1)
Where:
- Original point.
- Translated point.
- Translation vector.
If we know that and
, then the translation vector is:
It can be proved that the circle R is similar to the circle Q by translating the circle R a displacement of (-6, 12).
