123 is more than 1 because it is positive and 123 is also positive so the farther away from 0 is greater on the positive side and less on the negative side

4 0

3 years ago

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For each of the finite geometric series given below, indicate the number of terms in the sum and find the sum. For the value of

kotykmax [81]

Answer:

Number of term N = 9

Value of Sum = 0.186

Step-by-step explanation:

From the given information:

Number of term N = $3 (0.5)^{5} + 3 (0.5)^{6} + 3 (0.5)^{7} + \cdots + 3 (0.5)^{13}$

Number of term N = $3 (0.5)^{5} + 3 (0.5)^{6} + 3 (0.5)^{7} +3 (0.5)^{8}+3 (0.5)^{9} +3 (0.5)^{10} +3 (0.5)^{11}+3 (0.5)^{12}+ 3 (0.5)^{13}$

Number of term N = 9

The Value of the sum can be determined by using the expression for geometric series:

$\sum \limits ^n_{k=m}ar^k =\dfrac{a(r^m-r^{n+1})}{1-r}$

here;

m = 5

n = 9

r = 0.5

Then:

$\sum \limits ^n_{k=m}ar^k =\dfrac{3(0.5^5-0.5^{9+1})}{1-0.5}$

$\sum \limits ^n_{k=m}ar^k =\dfrac{3(0.03125-0.5^{10})}{0.5}$

$\sum \limits ^n_{k=m}ar^k =\dfrac{(0.09375-9.765625*10^{-4})}{0.5}$

$\sum \limits ^n_{k=m}ar^k =0.186$

6 0

3 years ago

A fruit stand has to decide what to charge for their produce. They need $10 for 44 apples and 44 oranges. They also need $15 for

Bess [88]

Step-by-step explanation:

Let x be the price of an apple and y be the price of an orange.

We have been given that a fruit stand need $10 for 4 apples and 4 oranges. We can represent this information as:

$4x+4y=10...(1)$

We are also told that they need $15 for 6 apples and 6 oranges. We can represent this information as:

$6x+6y=15...(2)$

Therefore, our desired system of equations will be:

$4x+4y=10...(1)$

$6x+6y=15...(2)$

4 0

3 years ago

What is the GCF of 20, 36 and 48

nlexa [21]

20= 1,2,4,5,10,20
36=1,2,3,4,6,9,12,18,36
48=1,2,3,4,6,8,12,16,24,48

6 0

3 years ago