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3 years ago

Ben is 12 years older than Ishaan. Ben and Ishaan first met two years ago. Three years ago, Ben was 4 times as old as Ishaan.

Mathematics

2 answers:

inessss [21]3 years ago

7 0

Yea I'd say 19 as welll

Andrej [43]3 years ago

6 0

Ben should be 19 years old.

What are your options?

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Find the inverse of the following equation: y=2x-3

Elina [12.6K]

Step-by-step explanation:

First get x on its own:

Subtract 3 from each side

y - 3 = 2x

Divide through by 2

y/2 - 3/2 = x

or x = y/2 - 3/2

Now simply switch labels: x↔y

y = x/2 - 3/2

8 0

3 years ago

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The CBGC pays college and high school students $5.75 per hour to tutor the younger boys and girls. If one of those tutors works

Levart [38]

Answer:

1. $35.075

2. 43.5 hours

3. 70%

4. Danny is correct

5. Abe's score out of the 30 points of the last quiz to get an overall checkup quiz grade of 80% should be 28.5

Step-by-step explanation:

The pay per hour for student tutors = $5.75

1. A tutor who worked 3.4 hours on Monday and 2.7 hours on Thursday has worked, 3.4 + 2.7 = 6.1 hours for the week, therefore

The week earning for the tutor = 6.1 × 5.75 = $35.075

2. The Club's tutoring budget per week = $250

The number of tutoring hours that can be provided per week is given by the relation;

$\frac{The \, Club's \ tutoring\ budget \ per \, week}{The \, pay \ per \, hour\, for\, student\, tutors} = \frac{\$250}{\$5.75/hour} = 43.47826 \approx 43.5 \, hours$

3. The score of 21 out of 30 as a percentage is given as follows;

$\frac{21}{30} \times 100 = 70\%$

4. Where the second score is 45 out of a total of 60 points, we have;

$\frac{45}{60} \times 100 = 75\%$

Therefore, the increase in Abe's score is 5%, therefore, Danny is correct

5. To raise his checkup quiz grade to 80% overall, then we should have;

$\frac{70 + 75 + Q}{300} =\frac{80}{100}$

Where:

Q = The percentage grade of the last quiz

(145 + Q)×100 = 80×300 = 24000

145 + Q = 240

Q = 240 - 145 = 95%

Therefore, he has to score, 95% of 30 on the last quiz, which is thus;

$\frac{95}{100} \times 30 = 28.5$

Abe's score out of the 30 points of the last quiz to get an overall checkup quiz grade of 80% = 28.5 points.

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3 years ago

Tina wants to run 123 miles over

Alinara [238K]

She must run about 17.5 miles a day

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3 years ago

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What is the greatest perfect square that is a factor of 980?

BaLLatris [955]

Since 980÷2=490÷2=245÷5=49÷7=7÷7=1
980=2×2×5×7×7
the greatest perfect square will be
7*2*7*2
14*14=196

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3 years ago

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This figure is made up of a quadrilateral and a semicircle.

Arturiano [62]

Answer:

The correct option is B. The area of the figure is 40.4 units².

Step-by-step explanation:

The line AB divides the figure in two parts one is a rectangle and another is semicircle.

The distance formula is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The length of AB is

$AB=\sqrt{(2+3)^2+(4-2)^2}=\sqrt{25+4}=\sqrt{29}$

The length of AD is

$AD=\sqrt{(-1+3)^2+(-3-2)^2}=\sqrt{4+25}=\sqrt{29}$

Since AB=AD, therefore ABCD is a square. The area of the of square is

$A_1=a\times a=\sqrt{29}\times \sqrt{29} =29$

The area of square is 29 units².

The area of a semicircle is

$A_2=\frac{\pi}{2}r^2$

Since AB is the diameter of the semicircle, therefore the radius of the semicircle is

$r=\frac{d}{2}=\frac{\sqrt{29}}{2}$

The area of the semicircle is

$A_2=\frac{3.14}{2}(\frac{\sqrt{29}}{2})^2=40.3825$

The area of the figure is

$A=A_1+A_2=29+11.2825=40.3825\approx 40.4$

Therefore the area of the figure is 40.4 units². Option B is correct.

5 0

3 years ago