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guapka [62]
2 years ago
6

I need this done, please I need to pass these six weeks! Thanks

Mathematics
1 answer:
Harlamova29_29 [7]2 years ago
5 0
For page 1:
4. H
5. B
6. F, G and H
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Evaluate x^0 + y^0 for x=3 and y=2
sveta [45]

x^0 + y^0

3^0 + 2^0

1 + 1 =2

your answer : 2

<u>Hint any number with the power of zero is 1</u>

Hope i helped!!! :)

3 0
3 years ago
onyango wishes to fence a rectangular research plot using 100 m of wire .one end of the plot has a wall already erected .calcula
earnstyle [38]

Answer:

1250 m²

Step-by-step explanation:

Let x and y denote the sides of the rectangular research plot.

Thus, area is;

A = xy

Now, we are told that end of the plot already has an erected wall. This means we are left with 3 sides to work with.

Thus, if y is the erected wall, and we are using 100m wire for the remaining sides, it means;

2x + y = 100

Thus, y = 100 - 2x

Since A = xy

We have; A = x(100 - 2x)

A = 100x - 2x²

At maximum area, dA/dx = 0.thus;

dA/dx = 100 - 4x

-4x + 100 = 0

4x = 100

x = 100/4

x = 25

Let's confirm if it is maximum from d²A/dx²

d²A/dx² = -4. This is less than 0 and thus it's maximum.

Let's plug in 25 for x in the area equation;

A_max = 25(100 - 2(25))

A_max = 1250 m²

5 0
3 years ago
Shannon scores 36 points on 6 questions on her test what is the unit rate for one question?
VLD [36.1K]

Answer:

Uh I think 6

Step-by-step explanation:


7 0
3 years ago
georges playground is shown in the diagram he wants to buy timber to put all around it so that mulch does not spread how much ti
Xelga [282]
He needs 84 ft.
Step by step explanation:
(24*2)+(18*2)
48+36
84
7 0
3 years ago
DATA ANALYSIS AND STATISTICSProbabilities involving two rolls of a dieAn ordinary (falr) die is a cube with the numbers 1 throug
Zepler [3.9K]

Solution

The table below is the required sample space of the to fair die

From the above table

The sample space contain 36 outcomes

Event A: The sum is greater than 9

we will look at the table and count all the elements that are greater than 9

There are 6 elements (they are 10, 10, 10, 11, 11, 12 from the table)

The probability for event A will be

\begin{gathered} p(A)=\frac{\text{required outcome}}{\text{total outcome}} \\ p(A)=\frac{6}{36} \\ p(A)=\frac{1}{6} \end{gathered}

P(A) = 1/6

Event B: The sum is an even number.

We will look at the table and count the number of elements that are even

There are 18 elements (notice that there are 3 even number on each of the 6 rows of the table)

The probability for event B will be

\begin{gathered} p(B)=\frac{\text{required outcome}}{\text{total outcome}} \\ p(B)=\frac{18}{36} \\ p(B)=\frac{1}{2} \end{gathered}

p(B) = 1/2

5 0
1 year ago
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