Sorry man, don’t know it, hopefully you get someone who knows
Answer:
it is -3+11x
Step-by-step explanation:
just look at your notes or take some
Answer:
a. 2300 + 4300 = 6600 since the number after 6 is greater than 5 it would round the number up 1 thousand.
7000
b. 4300 - 2100 = 2200 just stays the same
2000
c. 11 x 7 = 77 round up
80
d. 8 / 5 = 1.6 round up
2
Step-by-step explanation:
(I'm not sure if you have to use decimals or just random numbers)
a. 2300 + 4300 = 6600 since the number after 6 is greater than 5 it would round the number up 1 thousand.
7000
b. 4300 - 2100 = 2200 just stays the same
2000
c. 11 x 7 = 77 round up
80
d. 8 / 5 = 1.6 round up
2
To find out which equation has no real solutions, we need to calculate the discriminant for each of these given equations.
For calculating the discriminant, we need to first compare these equations with the general formula which is <u>ax²+bx+c.</u>
So, let's get started.
1) x² + 4x + 16 = 0
a=1, b=4, c=16
D = b²-4ac
= (4)² - 4(1)(16)
= 16-64
= -48
√D = √-48
2) 4x² + 4x - 24 = 0
a=4, b=4, c=-24
D = b²-4ac
= (4)² - 4(4)(-24)
= 16 - 16(-24)
= 16 + 384
= 400
√D = √400 = +20 or -20
3) 5x² + 3x - 1 = 0
a=5, b=3, c=-1
D = b²-4ac
= (3)² - 4(5)(-1)
= 9 + 20
= 29
√D = √29
4) 2x² - 4x + 4 = 0
a=2, b=-4, c=4
D = b²-4ac
= (-4)² - 4(2)(4)
= 16 - 32
= -16
√D = √-16
Now from all these above calculations, we can see that discriminant was negative in first equation and in last equation.
If D<0 then roots does not exist, as the square root can not contain a negative value or the equation does not have any real solutions.
Roots in such case can be calculated but those roots are known as imaginary roots, which is a higher concept.
So Final answer is,
Equation 1 => x² + 4x + 16 = 0
and
Equation 4 => 2x² - 4x + 4 = 0
has no real solutions.