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3 years ago

12 m 3 m 3 m 8 m 8 m

Mathematics

2 answers:

Natali5045456 [20]3 years ago

6 0

What’s the question

mestny [16]3 years ago

5 0

So the question is?? I need prove

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Amelia launched her science fair rocket, and then backed away. The path of the rocket is given by the equation below, where y is

Mamont248 [21]

Answer:

1)The rocket hit the ground at $x = \frac{5}{4}$

2)The maximum height of the rocket = 12.468 feet

Step-by-step explanation:

Step(i):-

Given equation

y = -2 x² + 5 x + 7 ...(i)

Differentiating equation (i) with respective to 'x' , we get

$\frac{dy}{dx} = -2( 2x) +5(1) = -4x +5$

Equating zero

$\frac{dy}{dx} = 0$

⇒ -4 x +5 =0

⇒ -4 x = -5

⇒ $x = \frac{5}{4}$

The rocket hit the ground at $x = \frac{5}{4}$

Step(ii):-

$\frac{dy}{dx} = -4x +5$ ...(ii)

Again differentiating equation (ii) with respective to 'x' , we get

$\frac{d^{2} y}{dx^{2} } = - 4(1)$

The maximum height at x = $\frac{-5}{4}$

y = -2 x² + 5 x + 7

$y = -2 (\frac{5}{4})^{2} + 5 (\frac{5}{4} ) + 7$

$y = \frac{-2(25)+ 25 (16)+7(64)}{64}$

$y = \frac{798}{64} = 12.468 feet$

The maximum height of the rocket = 12.468 feet

4 0

3 years ago

Mathhh time! No files or jokes pls

cestrela7 [59]

Answer:2.50cm

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Value expression 0.5*2

topjm [15]

0.5*2=1

Explanation: 0.5+0.5 =1

4 0

3 years ago

Read 2 more answers

Jane's cell phone plan is $58 each month plus $0.20 per minute for each minute over 200 minutes of call time. Jane's cell phone

Maksim231197 [3]

Answer: 45 minutes more than 200

Step-by-step explanation:

So for every minute over 200 jane has to pay 0.20 cents per additional minute. The equation we can use is $58+0.20m=$67 where m is the amount of minutes after 200 jane has to pay 20 cents per

58+0.20m=67

0.20m=9

m=45

So Jane was billed for 45 minutes over 200 minutes last month. so in total 245 minutes and she was charged for the extra 45 minutes

8 0

3 years ago

Simplify. Assume x and y are no negative

erica [24]

$7\sqrt{50x^{15}y^{21}}=7\sqrt{25\cdot2x^{14+1}y^{20+1}}=7\sqrt{25}\cdot\sqrt{x^{14}}\cdot\sqrt{y^{20}}\cdot\sqrt{2xy}\\\\=7(5)\sqrt{(x^7)^2}\cdot\sqrt{(y^{10})^2}\cdot\sqrt{2xy}=35x^7y^{10}\sqrt{2xy}\\\\Used:\\\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{a^2}=a\\\\a^n\cdot a^m=a^{nm}\\\\(a^n)^m=a^{nm}$

5 0

3 years ago