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zimovet [89]
4 years ago
15

I need this answer for my math class thanks

Mathematics
1 answer:
Orlov [11]4 years ago
4 0

Answer:

is the difference between a rain forest and savanna?

Step-by-step explanation:

is the difference between a rain forest and savanna?

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Find the volume of a pyramid with a square base, where the side length of the base is 14.7 and the height of the pyramid is 17.2
Romashka-Z-Leto [24]

Answer: 1238.916

Step-by-step explanation:

A = (Bh)/3

B = 14.7 x 14.7

The area of a pyramid is the formula at the top. B in the formula at the top is the Base. The reason it is capitalized is because B is also a formula. You need to find the area of the base of the pyramid and plug it into the equation. It this case, the base is equal to the second equation above.

7 0
3 years ago
7(x – 3) – 5(2x - 4) = 5​
WITCHER [35]

Answer:

-2

Step-by-step explanation:

7x-21-10x+20=5

7x-10x-1=5

-3x=5+1

x=-6/3

x=-2

7 0
4 years ago
Read 2 more answers
Errors in an experimental transmission channel are found when thetransmission is checked by a certifier that detects missing pul
Ivahew [28]

Answer:

a) P(X \leq 4)

And we can find this using the cumulative distribution function:

P(X \leq 4) = F(4) = 0.9

b) P(X > 7)

And we can find this using the cumulative distribution function and the complement rule on this way:

P(X >7) =1-P(X\leq 7)= 1- F(7) = 1-1 = 0

c) P(X \leq 5)

And we can find this using the cumulative distribution function:

P(X \leq 5) = F(5) = 0.9

d) P(X > 4)

And we can find this using the cumulative distribution function and the complement rule on this way:

P(X >4) =1-P(X\leq 4)= 1- F(4) = 1-0.9 = 0.1

e) P(X \leq 2)

And we can find this using the cumulative distribution function:

P(X \leq 2) = F(2) = 0.7

Step-by-step explanation:

For this case we have the following cumulative distribution function:

F(x) = 0 , x

F(x) = 0.7, 1 \leq x

F(x) = 0.9, 4 \leq x

F(x) = 1, x \geq 7

Part a

We want this probability:

P(X \leq 4)

And we can find this using the cumulative distribution function:

P(X \leq 4) = F(4) = 0.9

Part b

We want this probability:

P(X > 7)

And we can find this using the cumulative distribution function and the complement rule on this way:

P(X >7) =1-P(X\leq 7)= 1- F(7) = 1-1 = 0

Part c

We want this probability:

P(X \leq 5)

And we can find this using the cumulative distribution function:

P(X \leq 5) = F(5) = 0.9

Part d

We want this probability:

P(X > 4)

And we can find this using the cumulative distribution function and the complement rule on this way:

P(X >4) =1-P(X\leq 4)= 1- F(4) = 1-0.9 = 0.1

Part e

We want this probability:

P(X \leq 2)

And we can find this using the cumulative distribution function:

P(X \leq 2) = F(2) = 0.7

7 0
3 years ago
Please help fast......
Tom [10]

3)

\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\ 1.AY=BX&\text{1. Given}\\ 2.AB \cong AB&\text{2. Reflexive Property}\\ 3. AD || BC&\text{3. Property of a square}\\ 4. \angle ABE \cong \angle AXB&\text{4. Alternate Interior Angles}\\ 5. \angle BAY \cong \angle BYA&\text{5. Alternate Interior Angles}\\6. \triangle BAX \cong \triangle ABY&\text{6. Angle-Side-Angle Theorem}\\ 7. AX \cong BY&\text{7. CPCTC}\\\end{array}

*************************************************************************************

6)

\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\1. AB=CF&\text{1. Given}\\2.AB+BF=A'F&\text{2. Segment Addition Postulate}\\3.CF+BF=A'F&\text{3. Substitution Property}\\4.CF+BF+BC&\text{4. Segment Addition Postulate}\\5.A'F=BC&\text{5. Transitive Property}\\6. \angle AFE = \angle DBC&\text{6. Given}\\7. EF = BD&\text{7. Given}\\8. \triangle AFE \cong \triangle CBD&\text{8. Side-Angle-Side Theorem}\\\end{array}

*************************************************************************************

7)

\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\\text{1.AC bisects }\angle BAD&\text{1. Given}\\2. \angle BAC \cong \angle DAC&\text{2. Property of angle bisector}\\3.AC = AC&\text{3. Reflexive Property}&4. \angle ACB \cong \angle ACD&\text{4. Property of angle bisector}\\5. \triangle ABC \cong \triangle ADC&\text{5. Angle-Side-Angle Theorem}\\6.BC=CD&\text{6. CPCTC}\\\end{array}

5 0
4 years ago
Can someone answer the question please.<br> Identify the vocabulary word that matches the picture. ​
kozerog [31]
There is no picture
6 0
4 years ago
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